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Bunuel
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Mark can paint twice as fast as Joe. If Mark starts to paint at one en 28 Apr 2017, 03:25
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B
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78% (01:34) correct 22% (01:40) wrong based on 410 sessions

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Mark can paint twice as fast as Joe. If Mark starts to paint at one end of a mile-long wall and Joe starts to paint at the other end of the wall, how far away from Mark's end of the wall will they meet?

A. 3/4 mile
B. 2/3 mile
C. 1/2 mile
D. 1/3 mile
E. 1/4 mile
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B
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BrentGMATPrepNow
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Mark can paint twice as fast as Joe. If Mark starts to paint at one en 28 Apr 2017, 06:14
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Bunuel
Mark can paint twice as fast as Joe. If Mark starts to paint at one end of a mile-long wall and Joe starts to paint at the other end of the wall, how far away from Mark's end of the wall will they meet?

A. 3/4 mile
B. 2/3 mile
C. 1/2 mile
D. 1/3 mile
E. 1/4 mile
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Mark can paint twice as fast as Joe.
For every 1 foot of fence that Joe paints, Mark paints 2 feet.
So, out of every 3 feet of fence that gets painted, Mark paints 2 feet
In other words, Mark does 2/3 of the work.

So, if their combined efforts yields 1 mile of painting, then we know that Mark completed 2/3 of the job.
So, Mark painted 2/3 miles of fence.

Answer:
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B

Cheers,
Brent
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Mark can paint twice as fast as Joe. If Mark starts to paint at one en 02 May 2017, 16:53
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Bunuel
Mark can paint twice as fast as Joe. If Mark starts to paint at one end of a mile-long wall and Joe starts to paint at the other end of the wall, how far away from Mark's end of the wall will they meet?

A. 3/4 mile
B. 2/3 mile
C. 1/2 mile
D. 1/3 mile
E. 1/4 mile
Show more

Since Mark can paint twice as fast as Joe, he will paint twice as much of the wall (length-wise) as Joe will. If we let x = the length of wall Joe paints, then 2x = the length of wall Mark paints. Therefore:

2x + x = 1

3x = 1

x = 1/3

Thus, Mark paints 2/3 of a mile of the wall, i.e., he is 2/3 of a mile from his end of the wall when he meets Joe.

Answer: B
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Mark can paint twice as fast as Joe. If Mark starts to paint at one en 02 May 2017, 04:36
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classic application of ratios,,,

given ratio of rate is 2:1,, hence distance covered will be 2:1

from mark's end distance covered will 2/3 of the total distance

ans B
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Mark can paint twice as fast as Joe. If Mark starts to paint at one en 07 Oct 2019, 10:55
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Through POE you can eliminate C,D,E..Because by time Joe did his 1/4 of a mile, mark would have completed 1/2 mille, meaning that at minimum Mark is 1/2 a mile away from his starting point;however, they together still have to complete 1/4 more of the mile which will push Mark even further from the 1/2 mile mark. So A, C, D, & E can be eliminated.
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Mark can paint twice as fast as Joe. If Mark starts to paint at one en 13 Dec 2022, 11:53
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BrentGMATPrepNow
Bunuel
Mark can paint twice as fast as Joe. If Mark starts to paint at one end of a mile-long wall and Joe starts to paint at the other end of the wall, how far away from Mark's end of the wall will they meet?

A. 3/4 mile
B. 2/3 mile
C. 1/2 mile
D. 1/3 mile
E. 1/4 mile

Mark can paint twice as fast as Joe.
For every 1 foot of fence that Joe paints, Mark paints 2 feet.
So, out of every 3 feet of fence that gets painted, Mark paints 2 feet
In other words, Mark does 2/3 of the work.

So, if their combined efforts yields 1 mile of painting, then we know that Mark completed 2/3 of the job.
So, Mark painted 2/3 miles of fence.

Answer:
Show Spoiler
B

Cheers,
Brent
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Hi Brent BrentGMATPrepNow, very great shortcut.
Just in case not thought of it at exam, could you show how to solve this using work rate formula? Thanks Brent
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Mark can paint twice as fast as Joe. If Mark starts to paint at one en 27 Feb 2024, 21:18
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Visualize

30 seconds via visualizing

<-------------|-------|------->
                Mark   Joe
                 1/2    1/4

The answer is between 1/2 and 1/4, answer B looked like the right position
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