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05 Jun 2017, 08:40
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Difficulty:
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Question Stats:
94% (00:48) correct
6%
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In the figure below, the grid consists of unit squares. What is the area of the polygon?
(A) 7
(B) 9
(C) 10
(D) 12
(E) 15
Attachment:
56565.jpg [ 10.66 KiB | Viewed 6668 times ]
05 Jun 2017, 16:44
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SajjadAhmad
The great thing about the "fancy" quadrilaterals (squares, parallelograms, rectangles, rhombuses, AND trapezoids) is that they all have the same area formula.
Area = (base)(height)
In the case of a trapezoid, there are two bases (the two parallel sides are considered the bases).
So, what do we do?
We use the average of the two bases
This figure features a trapezoid.
The bottom base has length 5 and the top base has length 2
So, the average of the two bases = (5+2)/2 = 3.5
So, the area of the figure = (base)(height) = (3.5)(2)
= 7
Answer:
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General Discussion
05 Jun 2017, 08:59
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The figure consists of
a square with side 2,
a triangle1 with height=base=2,
and a triangle2 with a height=2 and base=1.
The combined area
= Area of Square(2*2) + Area of triangle1(\(\frac{1}{2}*2*2\)) + Area of triangle2(\(\frac{1}{2}*2*1\))
= 4+2+1 = 7(Option A)
a square with side 2,
a triangle1 with height=base=2,
and a triangle2 with a height=2 and base=1.
The combined area
= Area of Square(2*2) + Area of triangle1(\(\frac{1}{2}*2*2\)) + Area of triangle2(\(\frac{1}{2}*2*1\))
= 4+2+1 = 7(Option A)
