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Re: In the figure below, the grid consists of unit squares. What is
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05 Jun 2017, 08:59
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The figure consists of a square with side 2, a triangle1 with height=base=2, and a triangle2 with a height=2 and base=1.
The combined area = Area of Square(2*2) + Area of triangle1(\(\frac{1}{2}*2*2\)) + Area of triangle2(\(\frac{1}{2}*2*1\)) = 4+2+1 = 7(Option A)
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Re: In the figure below, the grid consists of unit squares. What is
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05 Jun 2017, 16:44
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SajjadAhmad wrote:
In the figure below, the grid consists of unit squares. What is the area of the polygon?
(A) 7 (B) 9 (C) 10 (D) 12 (E) 15
Nova GMAT
The great thing about the "fancy" quadrilaterals (squares, parallelograms, rectangles, rhombuses, AND trapezoids) is that they all have the same area formula. Area = (base)(height)
In the case of a trapezoid, there are two bases (the two parallel sides are considered the bases). So, what do we do? We use the average of the two bases
This figure features a trapezoid. The bottom base has length 5 and the top base has length 2 So, the average of the two bases = (5+2)/2 = 3.5
So, the area of the figure = (base)(height) = (3.5)(2) = 7
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06 Jun 2017, 00:13
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We can also solve this question just by observation:
Notice that their are 5 Complete squares in this area. Their area in total = 1*5 = 5 There are 2 half squares on the left (two right angle triangles) whose area add up to area of 1 square = 1 On the right, there is one right angle triangle (whose base is 1 and height is 2). We can either calculate its area as 1/2 * 1 * 2 OR we can observe carefully that its area would be equal to that of one complete square. Area = 1
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19 Feb 2019, 01:04
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