Bunuel

The figure above is formed by two overlapping squares, each having sides of 6 centimeters in length. If P and Q are the midpoints of the intersecting sides, what is the area, in square centimeters, of the enclosed region?
(A) 72
(B) 63
(C) 60
(D) 54
(E) 45
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Method I - Add square areas and subtract overlap - Figure IEach square has a side of length 6 cm.
P and Q are midpoints.
Thus the sides of the squares are bisected.
In Figure 1, short sides of overlap = \(\frac{6}{2}\)= 3
\(cm\)The area of each square is (6 * 6) = 36
\(cm^2\)The area of the overlap is (3 * 3) = 9
\(cm^2\)Area of enclosed region in square centimeters?
Square + Square - Overlap
36 + 36 - 9 =
63Method II - Divide region into areas. Find and add the areas of each regionSee Figure 2: outline different interior areas of the enclosed figure
P and Q , being midpoints, bisect each side of 6 cm into 3 cm each
The short sides of the interior areas are 3 cm. The long sides are 6 cm
Upper left corner, square's area: (6 * 6) = 36
\(cm^2\) Area of small square: (3*3) = 9
\(cm^2\)Bottom rectangle's area: (3*6) = 18
\(cm^2\)Area of enclosed region in square centimeters?
Add regions' areas
36 + 9 + 18 =
63 ANSWER B