Last visit was: 23 Apr 2026, 08:43 It is currently 23 Apr 2026, 08:43
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
nkmungila
Joined: 07 Jun 2017
Last visit: 02 Jul 2019
Posts: 109
Own Kudos:
914
 [15]
Given Kudos: 60
Location: India
Concentration: Technology, General Management
GMAT 1: 660 Q46 V38
GPA: 3.6
WE:Information Technology (Computer Software)
Products:
GMAT 1: 660 Q46 V38
Posts: 109
Kudos: 914
 [15]
2
Kudos
Add Kudos
12
Bookmarks
Bookmark this Post
User avatar
Siva2021
Joined: 15 Feb 2017
Last visit: 06 Jan 2026
Posts: 55
Own Kudos:
503
 [4]
Given Kudos: 35
Posts: 55
Kudos: 503
 [4]
3
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
User avatar
vmelgargalan
Joined: 16 Jan 2017
Last visit: 15 Aug 2018
Posts: 54
Own Kudos:
Given Kudos: 2
GMAT 1: 620 Q46 V29
GMAT 1: 620 Q46 V29
Posts: 54
Kudos: 24
Kudos
Add Kudos
Bookmarks
Bookmark this Post
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 23 Apr 2026
Posts: 109,778
Own Kudos:
Given Kudos: 105,853
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,778
Kudos: 810,796
Kudos
Add Kudos
Bookmarks
Bookmark this Post
vmelgargalan
Why is the answer not A? by what is given, x must be negative, so x squared will always be larger, no?

A. If \(\frac{1}{x}\) is greater than \(x\), \(x^2\) is greater than \(x\)

1/x > x holds true for x < -1 and 0 < x < 1. If x < -1, then yes, x^2 > x but if 0 < x < 1, then x^2 < x.
User avatar
shashankism
Joined: 13 Mar 2017
Last visit: 19 Feb 2026
Posts: 608
Own Kudos:
712
 [2]
Given Kudos: 88
Affiliations: IIT Dhanbad
Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE:Engineering (Energy)
Posts: 608
Kudos: 712
 [2]
1
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
nkmungila
Which of the following is always correct?

A. If \(\frac{1}{x}\) is greater than \(x\), \(x^2\) is greater than \(x\)

B. If \(\frac{1}{x}\) is greater than \(x\), \(x\) is greater than \(x^2\)

C. If \(x^2\) is greater than \(x\), \(x^3\) is greater than \(x^2\)

D. If \(x^3\) is greater than \(x^2\), \(x^4\) is greater than \(x^3\)

E. If \(x^4\) is greater than \(x^3\), \(x^5\) is greater than \(x^4\)

A. 1/x > x
So, 0<x<1 (x^2<x)or x<-1(x^2>x)
NOT CORRECT

B. 1/x > x
So, 0<x<1 (x>x^2)or x<-1(x<x^2)
NOT CORRECT

C. x^2 > x
So, x>1(x^3 >X^2) or x<0 (x^3 < x^2)
NOT CORRECT

D. x^3 > x^2
So, x>1 (x^4>x^3)
CORRECT

E. x^4 > x^3 ~ x^2 > x (Same as C)
NOT CORRECT
User avatar
Nikkb
User avatar
Current Student
Joined: 02 Jul 2017
Last visit: 08 Jan 2024
Posts: 226
Own Kudos:
318
 [3]
Given Kudos: 70
Concentration: Entrepreneurship, Technology
GMAT 1: 730 Q50 V38
2
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Which of the following is always correct?

A. If \(\frac{1}{x}\) is greater than \(x\), \(x^2\) is greater than \(x\)

\(\frac{1}{x}\) is greater than \(x\) => Either x = fraction ( between 0 and 1) or negative (less than -1)

if x = fraction => \(\frac{1}{(1/2)}\) > \(\frac{1}{2}\)
=> \(x^2\) is greater than \(x\) False

if x = negative => \(\frac{1}{(-2)}\) > \(-2\)
=> \(x^2\) is greater than \(x\) True

2 different solutions. So equation not always true

B. If \(\frac{1}{x}\) is greater than \(x\), \(x\) is greater than \(x^2\)


Same as above
\(\frac{1}{x}\) is greater than \(x\) => Either x = fraction ( between 0 and 1) or negative (less than -1)

if x = fraction => \(\frac{1}{(1/2)}\) > \(\frac{1}{2}\)
=> \(x\) is greater than \(x^2\) True

if x = negative => \(\frac{1}{(-2)}\) > \(-2\)
=>\(x\) is greater than \(x^2\) False

2 different solutions. So equation not always true


C. If \(x^2\) is greater than \(x\), \(x^3\) is greater than \(x^2\)

\(x^2\) is greater than \(x\) => either x =-ve or x=+ve
if x =-ve => \(x^3\) is greater than \(x^2\) False
if x =+ve => \(x^3\) is greater than \(x^2\) True

2 different solutions. So equation not always true

D. If \(x^3\) is greater than \(x^2\), \(x^4\) is greater than \(x^3\)

\(x^3\) is greater than \(x^2\) => For this condition to be true. x need to be +ve and greater than 1.

And for above value of x => \(x^4\) will always be greater than \(x^3\)

1 solution. Always true condition
Answer


E. If \(x^4\) is greater than \(x^3\), \(x^5\) is greater than \(x^4\)

\(x^4\) is greater than \(x^3\) => either x =-ve or x=+ve
if x =-ve => \(x^5\) is greater than \(x^4\) False
if x =+ve => \(x^5\) is greater than \(x^4\) True

Answer:D
User avatar
samarth1222
Joined: 30 Dec 2021
Last visit: 31 Dec 2024
Posts: 48
Own Kudos:
11
 [1]
Given Kudos: 71
Posts: 48
Kudos: 11
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
hi
Can someone please provide a strategy to deal with these types of questions generally I face problems in considering different numbers for these types of questions or sometimes forget to consider all the cases so someone can provide an easy way of solving them?

Thanks
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,963
Own Kudos:
Posts: 38,963
Kudos: 1,117
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Math Expert
109778 posts
Tuck School Moderator
853 posts