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04 Dec 2017, 03:38
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
81% (01:18) correct
19%
(01:31)
wrong
based on 60
sessions
History
Date
Time
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Not Attempted Yet
The sum of the areas of the faces of a cube is 300 square inches. The volume of this cube, in cubic inches, is
(A) 125√2
(B) 250√2
(C) 300√2
(D) 2,500
(E) 125,000
(A) 125√2
(B) 250√2
(C) 300√2
(D) 2,500
(E) 125,000
Luckisnoexcuse
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Joined: 18 Aug 2016
Last visit: 31 Mar 2026
Posts: 513
Given Kudos: 198
Concentration: Strategy, Technology
Schools: Kenan-Flagler '20 (M)
GMAT 1: 630 Q47 V29
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04 Dec 2017, 04:31
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Bunuel
\(6a^2 = 300\)
\(a = 5\sqrt{2}\)
\(a^3 = 250 \sqrt{2}\)
B
04 Dec 2017, 04:50
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Be aware - the question ask volume in cubic cm
Given - surface area =300
6*a^2=300
Side = 5\sqrt {2}\ INCHES
Volume =a^3* (2.54)^3 cubic cm
( 1 inch =2.54 cm)
No need to calculate
Imo E
Sent from my ONEPLUS A3003 using GMAT Club Forum mobile app
Given - surface area =300
6*a^2=300
Side = 5\sqrt {2}\ INCHES
Volume =a^3* (2.54)^3 cubic cm
( 1 inch =2.54 cm)
No need to calculate
Imo E
Sent from my ONEPLUS A3003 using GMAT Club Forum mobile app
