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henrymba2021
An arithmetic sequence of numbers begins p, 2p + 2, 4p + 3... What is the 13th member of this sequence?

A. 37
B. 40
C. 26p + 13
D. 53
E. 129p + 13

We are given p,2p + 2, and 4p + 3.... as the sequence.
If p = 1, the sequence becomes 1,4,7.....

Here First term(a) = 1, Common difference(d) = 3

Therefore, the 13th member of this sequence must be \(a + 12d = 1 + 12*3 = 1 + 36 = 37\) (Option A)

hi pushpitkc
why you have chosen P = 1 ...???
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sobby
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henrymba2021
An arithmetic sequence of numbers begins p, 2p + 2, 4p + 3... What is the 13th member of this sequence?

A. 37
B. 40
C. 26p + 13
D. 53
E. 129p + 13

We are given p,2p + 2, and 4p + 3.... as the sequence.
If p = 1, the sequence becomes 1,4,7.....

Here First term(a) = 1, Common difference(d) = 3

Therefore, the 13th member of this sequence must be \(a + 12d = 1 + 12*3 = 1 + 36 = 37\) (Option A)

hi pushpitkc
why you have chosen P = 1 ...???

Hey sobby

When I tried p=2 or 3, the emerging sequence was not having a common difference.
An arithmetic sequence has a common difference. That is the reason I chose p=1
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Given: An arithmetic sequence of numbers begins p, 2p + 2, 4p + 3.

Asked: What is the 13th member of this sequence?

Common difference = d = (2p + 2) - p = (4p+3) - (2p+2)
p + 2 = 2p + 1
p = 1

Arithmetic sequence = 1, 4, 7...
a = 1
d = 3
n = 13

\(t_13 = a + (n-1)d = 1 + 12*3 = 37\)

IMO A
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In any sequence, differences between subsequent terms are equal.

(2P+2)-P=(4P-3)-(2P+2). From this equation P=1.

sobby
pushpitkc
henrymba2021
An arithmetic sequence of numbers begins p, 2p + 2, 4p + 3... What is the 13th member of this sequence?

A. 37
B. 40
C. 26p + 13
D. 53
E. 129p + 13

We are given p,2p + 2, and 4p + 3.... as the sequence.
If p = 1, the sequence becomes 1,4,7.....

Here First term(a) = 1, Common difference(d) = 3

Therefore, the 13th member of this sequence must be \(a + 12d = 1 + 12*3 = 1 + 36 = 37\) (Option A)

hi pushpitkc
why you have chosen P = 1 ...???
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If someone didn't pay attention (like I Didn't) and scratched their heads about "how to generate the next terms of this series?"
I was not paying attention to the term "Arithmetic Sequence" is same as "Arithmetic Progression" which means the question is simply stating that the terms are in AP.

So, find the common difference and generate T13 as A+12D = 1 + 12(3) = 37. Option A
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