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Nixondutta
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A box contains 9 candles numbered from 1 to 9. If a candle is select Updated on: 09 Apr 2018, 01:22
Originally posted by Nixondutta on 08 Apr 2018, 23:59.
Last edited by Bunuel on 09 Apr 2018, 01:22, edited 1 time in total.
Edited the question.
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A box contains 9 candles numbered from 1 to 9. If a candle is selected from the box, find the probability that the number of the selected candle will be even or prime?

a. 8/9
b. 7/9
c. 2/3
d. 2/9
e. 1/9


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B
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A box contains 9 candles numbered from 1 to 9. If a candle is select 09 Apr 2018, 00:34
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Nixondutta
A box contains 9 candles numbered from 1 to 9. If a candle is selected from the box, find the probability that the number of the selected candle will be even or prime?
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a.8/9
b.7/9
c.2/3
d.2/9
e.1/9
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e(n)=2,3,4,5,6,7,8=7
s(n)=1..9=9

p(e)=7/9

B
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A box contains 9 candles numbered from 1 to 9. If a candle is select 03 Sep 2018, 06:55
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Nixondutta
A box contains 9 candles numbered from 1 to 9. If a candle is selected from the box, find the probability that the number of the selected candle will be even or prime?

a. 8/9
b. 7/9
c. 2/3
d. 2/9
e. 1/9


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Dear Moderator,
Found this probability question under combination section, hope you will do the needful. Thank you.
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A box contains 9 candles numbered from 1 to 9. If a candle is select 03 Sep 2018, 06:56
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Nixondutta
A box contains 9 candles numbered from 1 to 9. If a candle is selected from the box, find the probability that the number of the selected candle will be even or prime?

a. 8/9
b. 7/9
c. 2/3
d. 2/9
e. 1/9


Source- time4education

Dear Moderator,
Found this probability question under combination section, hope you will do the needful. Thank you.
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_______________
Edited. Thank you.
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A box contains 9 candles numbered from 1 to 9. If a candle is select 03 Sep 2018, 10:18
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Total = 9 candles
Even = 2,4,6,8
Prime=2,3,5,7
Probability = Fav/Total = 7/9

Hence IMO B
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A box contains 9 candles numbered from 1 to 9. If a candle is select 03 Sep 2018, 13:53
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1 2 3 4 5 6 7 8 9

P(Even) = P(2, 4, 6, 8) = 4/9
P(Prime) = P(2, 3, 5, 7) = 4/9
P(Even & Prime) = P(2) = 1/9

P(Even or Prime) = P(Even) + P(Prime) - P(Even & Prime)
= 4/9 + 4/9 - 1/9
= 7/9

Answer: (B)
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A box contains 9 candles numbered from 1 to 9. If a candle is select 07 Sep 2018, 17:08
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Nixondutta
A box contains 9 candles numbered from 1 to 9. If a candle is selected from the box, find the probability that the number of the selected candle will be even or prime?

a. 8/9
b. 7/9
c. 2/3
d. 2/9
e. 1/9
Show more

The probability of an even number is 4/9, the probability of a prime number is 4/9, and the probability of an even prime number is 1/9, so the probability of an even or prime number is 4/9 + 4/9 - 1/9 = 7/9.

Alternate Solution:

Among all the numbers between 1 and 9, the numbers 2, 3, 4, 5, 6, 7 and 8 satisfy the condition of being either an even number or a prime number. Thus, the probability is 7/9.

Answer: B
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A box contains 9 candles numbered from 1 to 9. If a candle is select 24 Jun 2021, 07:18
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