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10 Apr 2018, 00:01
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
72% (00:41) correct
28%
(00:43)
wrong
based on 258
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A square of side x has the length of each of its sides doubled. Its new area is what percent of its original area?
A. 100
B. 200
C. 300
D. 400
E. 500
A. 100
B. 200
C. 300
D. 400
E. 500
10 Apr 2018, 00:16
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Solution
Given:
- • The initial side length of the square is x.
• The side of square is doubled i.e. new side length is 2x.
To find:
- • We need to find that new area of the square is what percentage of the initial area.
Approach and Working:
- • Initial area of the square=\(x^2\)
• New area of the square= \((2x)^2\)= \(4x^2\)
Now, we need to find \(4x^2\)is what percentage of \(x^2\).
- • \(\frac{4x^2}{x^2}\)*100
• =4*100= 400
Hence, the correct answer is option D.
Answer: D
10 Apr 2018, 02:10
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Bunuel
Small Square, Side = x
Area = x^2
Big Square, Side = 2x
Area = (2x)^2 = 4x^2
New area as percentage of previous area = (New Area / Old Area)*100 = (4x^2 / x^2)*100 = 400%
ANSWER: OPTION D
Alternative:
The area is square of side so ratio of area grows by sqaure of ratio of sides
Since ratio of sides = 1/2
therefore ratio of areas = (1/2)^2 = 1/4
Hence new area = 400% of old area
