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Let Z= 100,

Y = 40 % less than Z = 60 % of Z= 60

X = 60% more than Y = 160% of Y = 160/100 *60 = 96

Hence X is 96% of Z

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Bunuel
If X is 60 percent more than Y and Y is 40 percent less than Z, then what percent of Z is X?

(A) 64%
(B) 80%
(C) 96%
(D) 120%
(E) 124%

X=>1.6Y or Y = X/1.6
Y= (1-0.4)Z or 06.Z
x/1.6 = .6Z=> X = .96Z
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Bunuel
If X is 60 percent more than Y and Y is 40 percent less than Z, then what percent of Z is X?

(A) 64%
(B) 80%
(C) 96%
(D) 120%
(E) 124%

\(x = 1.6 y\)

\(y =0.6 z\)

\(x = 1.6 * 0.6 z\)

\(\frac{x}{z}= 1.6 * 0.6\)

I will check the unit digit of the multiplication. It should be 6

Only one answer choice with unit digit 6

Answer: C
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Bunuel
If X is 60 percent more than Y and Y is 40 percent less than Z, then what percent of Z is X?

(A) 64%
(B) 80%
(C) 96%
(D) 120%
(E) 124%

We can create the equations:

X = 1.6Y

X = 8Y/5

And

Y = 0.6Z

Y/0.6 = Z

10Y/6 = Z

5Y/3 = Z

So X/Z x 100 is:

(8Y/5)/(5Y/3) x 100 = 24Y/(25Y) x 100 = 24/25 x 100 = 96

Alternate Solution:

We can create two equations:

X = 1.6Y

X/1.6 = Y

and

Y = 0.6Z

Since we have two equations, each equal to Y, we can set the two equations equal to each other:

X/1.6 = 0.6Z

X = 0.96Z

Thus, X is 0.96 x 100 = 96% of Z.

Answer: C
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