2^3^2*3^2*12^(-2) =

Question

2^{3^2}*3^2*12^{(-2)} =

A. 2
B. 4
C. 8
D. 16
E. 32

doomedcat · Answer

2^3^2 = 2^9, 12^-2 =  \frac{1}{12*12}  =  \frac{1}{(2^4 * 3^2)}

so now it becomes =>  \frac{(2^9 * 3^2)}{(2^4 * 3^2)}  = 2^5 = 32 ans E

balaji4799 · Answer

Interesting question. Higher chances to overlook simple concepts. 
the question (2^3)^2*3^2*12^-2 = 2^6*3^2/(2^4*3^2) = 2^2 = 4 Option B right answer

mskx · Answer

(2^3)^2 * 3^2 * 12^(-2)

rewrite: 2^6 * 9 * 1/144

= 64 * 9 * 1/144
=576/144
=4

B

doomedcat · Answer

pls refer below snap from gmat club math book

Hope i guess the stated exponent falls under last example in the snap

AkshdeepS · Answer

2^{3^2}*3^2*12^{(-2)} =

2^9*3*3*\frac{1}{12}*\frac{1}{12}

Solving we get,

32 (E)

generis · Answer

2^{3^2}*3^2*12^{(-2)} =

\frac{2^9*3^2}{12^2}=\frac{2^9*3^2}{4^2*3^2}=\frac{2^9*3^2}{(2^2)^2*3^2}=

\frac{2^9*3^2}{2^4*3^2}=2^{(9-4)}=2^5=32

Answer E

push12345 · Answer

(2)^9*(3)^2/(12*12)

=32

Posted from my mobile device

GyMrAT · Answer

2^{3^2}*3^2*12^{(-2)}  =  2^{9}*3^2/12^{2}  =  2^{9}*3^2/{(3*2^2)}^{2}  =  2^{9}*3^2/{(3^2*2^4)}  =  2^5  = 32.

Thanks,
GyM

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2^3^23^212^(-2) =

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