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26 Apr 2018, 13:33
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C
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Difficulty:
15%
(low)
Question Stats:
83% (01:08) correct
17%
(01:21)
wrong
based on 71
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Two consecutive angles of a parallelogram have angle measures, in degrees, of 2x - 30 and x + 60. What is the measure, in degrees, of the smaller angle?
(A) 50
(B) 60
(C) 70
(D) 100
(E) 110
(A) 50
(B) 60
(C) 70
(D) 100
(E) 110
26 Apr 2018, 15:06
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Bunuel
Two consecutive angles of a parallelogram have angle measures that add up to 180.
Therefore (2x-30) + (x+60) = 180
3x+30 = 180
3x = 150
x= 50
2x-30 = 70
x+60 = 110
Therefore the smaller angle is 70 degrees
Hence C = 70 is the answer.
27 Apr 2018, 00:14
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Bunuel
Ans: C
we know from theory that in a parallelogram opposite angles are equal and sum of all the interior angles is 360 so
2(2x-30)+2(x+60) = 360
x= 50
by putting this we get two angles = 70 and 110. smaller one is 70
Ans : C
