Given a positive integer c, how many integers are greater than c and

Question

Given a positive integer  c , how many integers are greater than c and less than  2c ?

A.  \frac{c}{2}

B.  c

C.  c - 1

D.  c - 2

E.  c + 1

KSBGC · Answer

let c be the 2. then 2c will be 4 . Now we can sort out the integers greater than c and less than 2c.

so, the integers are: 3 . check option: c-1 = 2-1=1. so our total number of integers will be 1.

let c be the 5 and 2c will be the 10. so integers greater than 5 and less than 10 are : 6 7 8 9 . In total 4 integers.

check option C. here c=5. then c-1 = 5-1 = 4. thus C is the correct answer as it meets the condition.

attari92 · Answer

Let there be some integer 'x' that lies between c and 2c. In accordance to the question prompt c+1<=x<=2c-1. Now, the problem boils down to how many integers lie between c+1 and 2c-1 => 2c-1-c-1+1 =c-1 => C

AkshdeepS · Answer

Say C = 3, then 2C = 6

So we have 3 < 4 < 5 < 6 : Two integers 4 and 5 are in between c and 2c.

Therefore, c - 1 is correct option

Try C = 5, then 2c = 10

So we have 6,7,8,9 : Four digits in between c and 2c.

So, c - 1 is correct option.

Hence (C)

arun6765 · Answer

Ans C
c-1.

let C=10 2C=20

in between, there are 9 integers 
so correct ans option C

saswata4s · Answer

Suppose C = 2; Hence, 2C = 4;
Integers between C and 2C, = 1(3) = C-1

Again, Suppose C = 4; Hence, 2C = 8;
Integers between C and 2C, = 3(5, 6, 7) = C-1

Hence, ans: C

manishred07 · Answer

If c=2 then 2c=4

2c-c=4-2=2 (but we have to select the number greater than 2 and smaller than 4)

hence there is actually 2-1=1 value only

Back to original question,

2c-c=c (This includes the extremes also, and hence we need to subtract 1)

Therefore, c-1 (option C is the correct answer)

ScottTargetTestPrep · Answer

Recall that the number of integers between two integers a and b, inclusive, is b - a + 1. However, here we want the numbers of integers between c and 2c, excluding themselves. Therefore, the number of integers is 2c - c + 1 - 2 = c - 1. Note that we subtracted 2 on the left side of the equation because we needed to exclude the endpoint values c and 2c.

Alternate Solution:

We can express the integers between c and 2c as c + 1, c + 2, … , c + (c - 1). Since c + 1 is the first integer, c + 2 is the second integer and so on, c + (c - 1) is the c - 1st integer.

Answer: C

ThatDudeKnows · Answer

There's a variable in the question that's repeated in the answer choices, so let's look to Plug In for c. Let's make c=1. How many integers are there between 1 and 2? Zero.

A.  \frac{1}{2} 
Eliminate.

B.  1 
Eliminate.

C.  1-1 = 0 
Keep it.

D.  1 - 2 = -1 
Eliminate.

E.  1 + 1 = 2 
Eliminate.

Answer choice C.

Rikhraj1 · Answer

Bunuel  pls explain this, i m not able to understand from above explanations

Given a positive integer c, how many integers are greater than c and

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GMAT Problem Solving (PS) Questions

Given a positive integer c, how many integers are greater than c and

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