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Bunuel
The length of each edge of a cube equals 6. What is the distance between the center of the cube to one of its vertices?

A. \(3 \sqrt{2}\)

B. \(6 \sqrt{2}\)

C. \(3 \sqrt{3}\)

D. \(4 \sqrt{3}\)

E. \(6 \sqrt{3}\)

The distance between the center of the cube to one of its vertices is half the length of the space diagonal of the cube. A space diagonal of a cube is the diagonal from one vertex of the cube to another vertex where the two vertices are not on the same face of the cube. Furthermore, if each edge of a cube has length s, then the space diagonal has a length of s√3.

We see that the space diagonal of the cube is 6√3, so half of that is 3√3.

Answer: C
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The length of each edge of a cube equals 6. What is the distance between the center of the cube to one of its vertices?

Known Information:
The length of each edge of cube equals 6.

We know that distance between 2 edges of a cube is equal to diagonal. So we have the diagonal as 63.

Question:
What is the distance between the center of the cube to one of its vertices?

Since question ask distance between center of cube to one of its vertices, we need to divide the value of diagonal by half.

6\(\sqrt{3}\) / 2 = 3\(\sqrt{3}\)

Ans: C
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Bunuel
The length of each edge of a cube equals 6. What is the distance between the center of the cube to one of its vertices?

A. \(3 \sqrt{2}\)

B. \(6 \sqrt{2}\)

C. \(3 \sqrt{3}\)

D. \(4 \sqrt{3}\)

E. \(6 \sqrt{3}\)
.

Solution:-

the distance between the center of the cube to one of its vertices = half the length of diagonal of cube.

diagonal of one side of cube is nothing but diagonal of square. Diagonal of square = \(\sqrt{6^2 + 6^2}\) = \(6\sqrt{2}\)

Diagonal of Cube = \sqrt{(6[square_root]2})^2 + 6^2[/square_root] = \(\sqrt{72 + 36}\) = \(\sqrt{108}\) = \(6\sqrt{3}\)

the distance between the center of the cube to one of its vertices = \(\frac{6}{2} * \sqrt{3}\) = \(3\sqrt{3}\)

Ans - C
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