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let second number be a

given (K+a)/2 = 35
a = 70-k

Ans D
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Bunuel
If the average (arithmetic mean) of two numbers is 35 and one of the numbers is k, then what is the other number, in terms of k ?

A. 35 + k
B. 35 – k
C. 35 − 2k
D. 70 – k
E. 70 − 2k


a+k=70
a=70-k
IMO D
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Bunuel
If the average (arithmetic mean) of two numbers is 35 and one of the numbers is k, then what is the other number, in terms of k ?

A. 35 + k
B. 35 – k
C. 35 − 2k
D. 70 – k
E. 70 − 2k

If the average of 2 numbers is 35, then the total of those 2 numbers is 70. if one of those numbers is K then the other should be 70-k. The answer seems to be D.

Hope moderator will provide the explanation for E or change the OA to D.
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Bunuel
If the average (arithmetic mean) of two numbers is 35 and one of the numbers is k, then what is the other number, in terms of k ?

A. 35 + k
B. 35 – k
C. 35 − 2k
D. 70 – k
E. 70 − 2k

Let n = the other number. We can create the equation:

(n + k)/2 = 35

n + k = 70

n = 70 - k

Answer: D
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Theory: Average = \(\frac{Sum Of All The Values}{Total Number Of Values}\)

If the average (arithmetic mean) of two numbers is 35 and one of the numbers is k
Let other number be x
=> Sum of all the values= k + x

Using, Average = \(\frac{Sum Of All The Values}{Total Number Of Values}\), We get
35 = \(\frac{k+x}{2}\)
=> k + x = 35*2 = 70
=> x = 70-k

So, Answer will be D
Hope it helps!

To learn more about Statistics watch the following video

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