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Bunuel
When the positive integer x is divided by 42, the remainder is 19. What is the remainder when x is divided by 7?

A. 0
B. 2
C. 3
D. 4
E. 5
Test values
List a few values that \(x\) could be

\(42+19=61\)
That is, \(((42*1) + 19)=61\)

After the first possibility, just add 42
\(61+42=103\)
That is, \(((42*2)+19)=103\)

\(103+42=145\)
That is, \(((42*3)+19)=145\)

\(x=61, 103, 145\) . . .

Remainder when \(x\) is divided by 7?

First \(x\) value: \(\frac{61}{7}=8\), Remainder 5

\(x\) divided by 7 = remainder of 5 should be the answer. Check

Next value of \(x\): \(\frac{103}{7}=14\), Remainder 5

Last value \(x\): \(\frac{145}{7}=20\), Remainder 5

When \(x\) is divided by 7, the remainder is 5

Answer E
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When the positive integer x is divided by 42, the remainder is 19

Theory: Dividend = Divisor*Quotient + Remainder

x -> Dividend
42 -> Divisor
a -> Quotient (Assume)
19 -> Remainders
=> x = 42*a + 19 = 42a + 19

What is the remainder when x is divided by 7

x = 42a + 19 = 7*6a + 14 + 5 = 7*61 + 7*2 + 5 = 7*(6a+2) + 5

=> x when divided by 7 gives 5 remainder

So, Answer will be E
Hope it helps!

Watch the following video to learn the Basics of Remainders

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