Martha biked 18 2/3 miles in 2 hours and 40 minutes. What was her aver

Question

Martha biked  18 \frac{2}{3}  miles in 2 hours and 40 minutes. What was her average rate of speed in miles per hour?

A. 7

B.  7 \frac{2}{3}

C.  8 \frac{1}{3}

D. 9

E.  9 \frac{1}{3}

D3N0 · Answer

Ans: A
Miles = 56/3 miles Time taken: 2 +2/3 hrs = 8/3 hrs
Velocity = Miles/Time = 7 miles/hrs

sudarshan22 · Answer

Distance =  18 \frac{2}{3}  = 56 / 3 miles
Time = 2 hours + 40 minutes = 2 hrs + 2 / 3 hrs = 8 / 3 hrs

Speed = Distance / Time = 56/3 / 8/3 = 7 miles per hour

Hence,   A  .

devlin · Answer

18 \frac{2}{3} = \frac{56}{3} 
2 hours and 40 minutes equals to 160 minutes
Lets say that R is the average rate

\frac{56}{3R} = \frac{160}{60} 
 \frac{56}{3R} = \frac{8}{3} 
 \frac{56}{R} = 8 
Cross multiplication:
 56 = R*8 
 R = \frac{56}{8} 
 R = 7

Option A

ScottTargetTestPrep · Answer

Martha's average rate of speed was:

(56/3)/(2 2/3) = (56/3)/(8/3) = (56 x 3)/24 = 168/24 = 7 mph

Answer: A

Abhishek009 · Answer

D = 18 \frac{2}{3}=\frac{56}{3}

T = 2  hours and  40  minutes  = 2 \frac{40}{60} = 2 \frac{2}{3} = \frac{8}{3}

Thus,  S = \frac{56}{3}*\frac{3}{8}=7 , Answer must be (A)

Prep Toolkit