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If the sum of two numbers is 6, and the sum of their reciprocals is 15/8, what is the product of the two numbers?
A. 5/24
B. 5/16
C. 16/5
D. 25/4
E. 45/4
A. 5/24
B. 5/16
C. 16/5
D. 25/4
E. 45/4
Chethan92
Joined: 18 Jul 2018
Last visit: 21 Apr 2022
Posts: 900
Own Kudos:
Given Kudos: 95
Location: India
Concentration: Operations, General Management
Schools: IIMB EPGP'22 (M)
GMAT 1: 590 Q46 V25
GMAT 2: 690 Q49 V34
WE:Engineering (Energy)
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24 Aug 2018, 00:24
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Let the number be X and Y.
Given, X+Y = 6.
and \(\frac{1}{X}\)+\(\frac{1}{Y}\) = \(\frac{15}{8}\).
\(\frac{X+Y}{XY}\) = \(\frac{15}{8}\)
Substituting X+Y = 6.
We get \(\frac{6}{XY}\) = \(\frac{15}{8}\) or XY = \(\frac{16}{5}\).
C is the answer.
Given, X+Y = 6.
and \(\frac{1}{X}\)+\(\frac{1}{Y}\) = \(\frac{15}{8}\).
\(\frac{X+Y}{XY}\) = \(\frac{15}{8}\)
Substituting X+Y = 6.
We get \(\frac{6}{XY}\) = \(\frac{15}{8}\) or XY = \(\frac{16}{5}\).
C is the answer.
24 Aug 2018, 00:40
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Bunuel
Given , the sum of two numbers is 6.
If one number is n, then the other number is 6-n.
To find:- n*(6-n)
Given, the sum of their reciprocals is 15/8
Or, \(\frac{1}{n}+\frac{1}{6-n}=\frac{15}{8}\)
Or, \(\frac{6}{n(6-n)}=\frac{15}{8}\)
Or, \(n*(6-n)=\frac{8*6}{15}=\frac{16}{5}\)
Ans. (C)
