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2+4+6+8+3+5+7+9+n = 44+n

If n is 1 then median is 45/9 = 5

If n is 10 then median is 54/9 = 6

B is the answer.
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generis
Afc0892
2+4+6+8+3+5+7+9+n = 44+n

If n is 1 then median is 45/9 = 5

If n is 10 then median is 54/9 = 6

B is the answer.
Afc0892
Your method is perfect if n must equal 1 OR 10, because then the integers are consecutive and median = mean.

But median \(\neq\) mean if n = 2,3,4,5,6,7,8, or 9
n is an integer between 1 and 10, inclusive.

If n = 2, mean = \(\frac{46}{9}=5.1111\)
If n = 7, mean = \(\frac{51}{9}= 5.67\)

Just an issue with the method (absent a mention of extremes and why they work) :)

Got it. Thanks :-)
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2 4 6 8 n 3 5 7 9

In the list above, if n is an integer between 1 and 10, inclusive, then the median must be

2 3 4 5 6 7 8 9

Case 1: n <= 5
Median = 5

Case 2: n >= 6
Median = 6

IMO B
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Bunuel
2 4 6 8 n 3 5 7 9

In the list above, if n is an integer between 1 and 10, inclusive, then the median must be


A. 4 or 5
B. 5 or 6
C. 6 or 7
E. n
E. 5.5
­Hello,

I solved it visualizing the n position, without calcs. Equally spaced numbers so n+1/2 gives the position --> 9+1/2 = 5th position for both median and mean. Meaning: 
n-->1       n 2 3 4 5 6 7 8 9 
n-->10        2 3 4 5 6 7 8 9 n


 
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Bunuel
2 4 6 8 n 3 5 7 9

In the list above, if n is an integer between 1 and 10, inclusive, then the median must be


A. 4 or 5
B. 5 or 6
C. 6 or 7
E. n
E. 5.5
­Hello,

I solved it visualizing the n position, without calcs. Equally spaced numbers so n+1/2 gives the position --> 9+1/2 = 5th position for both median and mean. Meaning: 
n-->1       n 2 3 4 5 6 7 8 9 
n-->10        2 3 4 5 6 7 8 9 n


 ­
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