The largest possible cube is enclosed in a cylinder and has volume 64.

Question

The largest possible cube is enclosed in a cylinder and has volume 64. What is the volume of the cylinder if its height is 12?

A. 384π
B. 192π
C. 144π
D. 96π
E. 48π

NandishSS · Answer

Volume of Cube=64

a^3=64 ==> a=4

Radius =2\sqrt{2}

volume of the cylinder = πr^2(h)

Volume = π*8*12 = 96π

Hence D

brains · Answer

Ok . Here is my take. We know the volume of cube is 64 . So each side of cube will be 4 .

If we place the largest possible cube in a cylinder then the condition would be only this, The edge of all sides of cube will touch the cylinder circular wall. Hence a circle with a centre can be drawn where the radius will be the diagonal of square formed by cube. 
So we have a square of 4* 4 which is circumscribed by a circle. hence the diagonal of square will be diameter of cylindrical circular part.
I am attaching the screenshot for reference .

KarishmaB · Answer

The volume of a sphere is given by Side^3 = 64
So Side = 4

When a largest possible cube is enclosed in a cylinder, the diagonal of the bottom face of the cube will be the diameter of the cylinder. 
Diagonal of the bottom face =  4*\sqrt{2}

So radius of the cylinder =  (4*\sqrt{2})/2 = 2\sqrt{2}

Volume of the cylinder =  \pi*r^2 * h = \pi * (2\sqrt{2})^2 * 12 = 96\pi

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The largest possible cube is enclosed in a cylinder and has volume 64.

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The largest possible cube is enclosed in a cylinder and has volume 64.

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