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26 Sep 2018, 04:57
Kudos
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
15%
(low)
Question Stats:
83% (01:50) correct
17%
(02:27)
wrong
based on 251
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How many liters of Chemical A must be added to a 120-liter solution that is 25 percent Chemical A in order to produce a solution that is 40 percent Chemical A?
(A) 12
(B) 15
(C) 20
(D) 24
(E) 30
(A) 12
(B) 15
(C) 20
(D) 24
(E) 30
26 Sep 2018, 23:09
Kudos
Bookmarks
.25*120+x=.40(120+x)
100[.25*120+x=.40(120+x)]100
25*120+100x=40(120+x)
3000+100x=4800+40x
100x-40x=4800-3000
60x=1800
x=30
Posted from my mobile device
100[.25*120+x=.40(120+x)]100
25*120+100x=40(120+x)
3000+100x=4800+40x
100x-40x=4800-3000
60x=1800
x=30
Posted from my mobile device
04 Dec 2019, 23:58
Kudos
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Bunuel
This can be solved in two ways.
Method 1:
Let's assume that x liters of Chemical A is added.
Total Chemical A in the final mixture = x + 0.25 * 120 = x + 30 liters.
As per the given condition:
- \((x+30) = \frac{40}{100} * (x + 120)\)
\(5x + 150 = 2x + 240\)
\(3x = 90\)
\(x = 30\) liters.
Method 2: (Alligation)
