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Solution


Given:
    • All the employees of Company A and B work on the same project
    • The ratio of number of employees in company A to company B = 5: 6
    • Each employee of company A can do the work 3 times faster, when compared to each employee of company B

To find:
    • What fraction of the project is done by employees of company B

Approach and Working:
    • Let us assume that the number of employees in company A = 5x
      o Implies, the number of employees in company B = 6x

    • Now, let us assume that each employee of company A can do 'y' amount of work in one day
      o Implies, each employee of company B can do '3y' amount of work in one day

    • So, \(\frac{Work done by all the employees of company A}{Work done by all the employees of company B}\) = \(\frac{(5x * 3y)}{(6x * y)} = \frac{15}{6} = \frac{5}{2}\)

Therefore, the fraction of work done by employees of company B = \(\frac{2}{(2 + 5)} = \frac{2}{7}\)

Hence, the correct answer is Option B.

Answer: B

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Hi egmat

Can we use your LCM method in this type of problem ? I wasnt able to solve through LCM and ended up choosing 2/5.
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Hi egmat

Can we use your LCM method in this type of problem ? I wasnt able to solve through LCM and ended up choosing 2/5.

Hi,

Could you please show us, how you approached at solving this question, so that we can understand it in a better way :)

Regards,
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EgmatQuantExpert
All employees of Company A and Company B work together on some project. The ratio of number of employees in company A and company B is 5: 6, and each employee of company A can do the work 3 times faster than each employee of company B. What fraction of the project is done by the employees of company B?

    A. 5/18
    B. 2/7
    C. 2/5
    D. 5/7
    E. 18/23

To read all our articles:Must read articles to reach Q51


Ratio of number of employees:
\(A:B = 5:6\)
Since A works 3 times faster than B
Then ratio of the work being done:
\(Wa:Wb = 5*3 : 6 = 15 : 6\)

Hence total work = 6 + 15 = 21
Ratio of work done by B to the total work:
Wb:Wt = \(\frac{6}{21} = \frac{2}{7}\)
Hence B is the correct answer.
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hero_with_1000_faces
Hi egmat

Can we use your LCM method in this type of problem ? I wasnt able to solve through LCM and ended up choosing 2/5.

Hi,

Could you please show us, how you approached at solving this question, so that we can understand it in a better way :)

Regards,


Hi,

I am sorry, I discarded the worksheet, before I saw your reply. But I tried solving this again and I ended up with correct answer although it logically doesnt make sense to me, if you could review that would be great:



So, A : B, 5x : 6x

As the employees for A are three times more efficient, that means one employee of "A" can work as much as three employees of "B".
So 5 * 3 = 15, so the ratio 15x : 6x; so now taking the LCM of 15 and 6 we get 30, from here on my answer doesn't logically make sense to me.

for A 30/15 = 2

for B 30/6 = 5

so total work is "7" and therefore 2/7. after solving I realized the question is asking for the part of work done by "B".
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EgmatQuantExpert
All employees of Company A and Company B work together on some project. The ratio of number of employees in company A and company B is 5: 6, and each employee of company A can do the work 3 times faster than each employee of company B. What fraction of the project is done by the employees of company B?

    A. 5/18
    B. 2/7
    C. 2/5
    D. 5/7
    E. 18/23


Ratio of employees of \(\frac{Company A}{Company B}\) = \(\frac{5x}{6x}\)

Say rate of Company B's employee = R,

Then rate of Company A's employee =3R

As both worked for equal time, time for both = T

We know:

Employees x Rate x Time = Work

For company A 5x * 3R * T = 15xRT

For company B 6x * R * T = 6xRT

Total work = \(15xRT + 6xRT = 21xRT\)

Work Done by \(B = 6xRT\)

Required fraction = \(\frac{6xRT}{21xRT}\) = \(\frac{2}{7}\)
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The question as A works 3 times faster than B, so it should be 3x + x = 4x , if the statement was 3 times as faster as B , then it should be x. Please explain
EgmatQuantExpert
All employees of Company A and Company B work together on some project. The ratio of number of employees in company A and company B is 5: 6, and each employee of company A can do the work 3 times faster than each employee of company B. What fraction of the project is done by the employees of company B?


A. 5/18
B. 2/7
C. 2/5
D. 5/7
E. 18/23

To read all our articles:Must read articles to reach Q51

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EgmatQuantExpert
All employees of Company A and Company B work together on some project. The ratio of number of employees in company A and company B is 5: 6, and each employee of company A can do the work 3 times faster than each employee of company B. What fraction of the project is done by the employees of company B?

A. 5/18
B. 2/7
C. 2/5
D. 5/7
E. 18/23


Let's assume that there are 5 employees in company A and 6 employees in company B.

When 1 employee from company B does 1 unit of work, then 1 employee of company A does 3 units of work.

Work done by employees from company B = 6*1 = 6 units

Work done by employees from company A = 5*3 = 15 units units

Proportion of work done by company B = 6/(6+15) = 6/21
=3/7
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The solution seems really easy, i wasted my time doing actual calculation
CounterSniper


A/B = 5/6
we are given
when A does 1 unit of work
B does 1/3 units of work
so,
5 employees of A will do 5 units of work.
6 employees of B will do 6*\(\frac{1}{3}\) = 2 units of work

fraction of project done by employees of B = \(\frac{B}{A+B}\) =\(\frac{2}{7}\)
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