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Can anyone explain why it is 6pie rather than 8pie..?

Posted from my mobile device
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HarikaBurlakanti
Can anyone explain why it is 6pie rather than 8pie..?

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OA Was wrong, it is indeed D.
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OA for the question must be (D) post has been modified by ADMIN member, Bunuel...
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Abhishek009
OA for the question must be (D) post has been modified by ADMIN member, Bunuel...

Yes, edited the OA. Thank you all.
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side^2 = (diagonal^2)/2

side = 4
diagonal = 4√2
radius = 2√2

Area = 8π
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akurathi12
A square is inscribed in a circle. If the side of the same square is 4cm, what is the area of the circle?

A. 2π
B. 4π
C. 6π
D. 8π
E. None of these



When a square is inscribed in a circle,
\(r:a = 1:\sqrt{2}\)

\(r/4 = 1:\sqrt{2}\)

\(r = 2*\sqrt{2}\)

Area of circle \(= \pi*r^2 = \pi*(2*\sqrt{2})^2 = 8\pi\)

Answer (D)
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akurathi12
A square is inscribed in a circle. If the side of the same square is 4cm, what is the area of the circle?

A. 2π
B. 4π
C. 6π
D. 8π
E. None of these

diameter of circle = diagonal of square = 4 srt 2
radius = 2 sqrt 2
area : (2 sqrt 2)^2 * pi
: 8 pi
IMO D
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akurathi12
A square is inscribed in a circle. If the side of the same square is 4cm, what is the area of the circle?

A. 2π
B. 4π
C. 6π
D. 8π
E. None of these


Since the square is inscribed in the circle, the diagonal of the square is equivalent to the diameter of the circle. Thus, 4√2 = diagonal of square = diameter of circle.

So the radius is half the diameter, or 2√2, and thus the area is (2√2)^2 x π = 8π.

Answer: D
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