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Dear Afc0892 Bunuel

Why you assumed that "base" is radius and not diameter? :?


Regards
L
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LevanKhukhunashvili
Dear Afc0892 Bunuel

Why you assumed that "base" is radius and not diameter? :?


Regards
L
__________________
Edited to make it clear.
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LevanKhukhunashvili
Dear Afc0892 Bunuel

Why you assumed that "base" is radius and not diameter? :?


Regards
L

I had the same doubt. But I checked by considering the base as diameter and there were not any options. So concluded that it should be radius.

Bunuel sir, If you could edit the question. It'll help to understand better.

Posted from my mobile device
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Bunuel
Three metal cubes with edges of two will be dropped into an empty cylindrical tank with a base radius of 3 and a height of 8. The three cubes will take up what fraction of the volume of the tank?


A 1/3

B 1/π

C 3/π

D 1/(3π)

E 2/(3π)

vol of cyld : pi * r^2 * h = 9*8*pi = 72 pi
volf of 3 cubes : 2^3 * 3 = 24
so area of cube would be be 24/72 Pi = 1/ 3pi
IMO D
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Bunuel
Three metal cubes with edges of two will be dropped into an empty cylindrical tank with a base radius of 3 and a height of 8. The three cubes will take up what fraction of the volume of the tank?


A 1/3

B 1/π

C 3/π

D 1/(3π)

E 2/(3π)

IMO D

Given
side of cube = 2

Volume = side^3 = 8

Volume of 3 cubes =24

Volume of cylinder = π * 8 * 9 = 72 π

Fraction = Volume of 3 cubes / Volume of cylinder

= 1 / 3π
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