If N is an integer and 99

Question

If N is an integer and 99 < N^2 < 200, then N could have at most how many values?

A. Two
B. Four
C. Six
D. Eight
E. Ten

Hoozan · Answer

Given:-
99 < N^2 < 200
N is an integer

Inference:-
N is a perfect square

Solution:-
We need to find all the perfect squares that lie between 99 and 200 exclusive

10^2= 100
11^2= 121
13^2= 169
14^2= 196

Thus there are four values of N that satisfies the given constraint

(B)

KSBGC · Answer

where is 12. 12^2 = 144. a value belongs to this range.

**** u are dealing with perfect square thus u have to consider negative values too.

(-10)^2 =100
(10)^2 = 100

thus , for each positive value there will be a same negative value.

KSBGC · Answer

Minimum value of N = 10

Max value of N = 14.

N = 10, 11 , 12 , 13 , 14.

As we are dealing with perfect square , we must consider negative values too.

N = -10 , -11, -12, -13, -14.

There will be 10 values in total.

E is the correct answer.

KanishkM · Answer

so lets see, easiest approach will be just write the numbers between the range 99 < N^2 < 200

10,11,12,13,14

Five +ive, Five -ive integers since it is a square you can take both values.

Total 10

Archit3110 · Answer

N= 10,11,12,13,14
and - ve values of N would lie in range 99 < N^2 < 200
IMO E 10

bumpbot · Answer

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If N is an integer and 99 < N^2 < 200, then N could have at most how m

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