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kiran120680
Moderator - Masters Forum
Joined: 18 Feb 2019
Last visit: 27 Jul 2022
Posts: 706
Given Kudos: 276
Location: India
Schools: AGSM '20 EDHEC Sept 2019 Intake Great Lakes '21 IE
GMAT 1: 460 Q42 V13
GPA: 3.6
28 Feb 2019, 07:47
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
73% (02:55) correct
27%
(02:57)
wrong
based on 197
sessions
History
Date
Time
Result
Not Attempted Yet
Molly went to a gift shop to buy some Christmas cards. Due to insufficient money at that time, she decided to come back on the next day. The next day price per card was increased by $4 and she could buy 12 fewer cards than those she would have bought on the previous day for $135. What is the new price of each card? (Note: All the cards are equally priced).
A. 4
B. 5
C. 6
D. 9
E. 11
A. 4
B. 5
C. 6
D. 9
E. 11
28 Feb 2019, 20:46
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kiran120680
Various ways to do it..
(I) Use the choices..
A. 4... New price is 4, old price is 0... Not possible
B. 5... New price 5, old price 5-4=1.. Difference in cards = \(\frac{135}{1}-\frac{135}{5}=135-27\neq{12}\)
C. 6.. New price 6, old price 6-4=2.. Difference in cards = \(\frac{135}{2}-\frac{135}{6}\neq{12}\)
D. 9.. New price 9, old price 9-4=5.. Difference in cards = \(\frac{135}{5}-\frac{135}{9}=27-15=12\) YES
E. 11.. New price 11, old price 11-4=7.. Difference in cards = \(\frac{135}{7}-\frac{135}{11}\neq{12}\) Answer cannot be in fractions
(II) Algebraic
New price x and old price x-4..
\(\frac{135}{x-4}-\frac{135}{x}=135*\frac{x-x+4}{x(x-4)}=12.....135*4=12x^2-48x....x^2-4x-45=0.....(x-9)(x+5)=0\)
Hence x can be 9 or -5. Cannot be negative, so x=9
D
General Discussion
Archit3110
03 Mar 2019, 03:59
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let price of card be x $
so with 135$ , Molly could buy ; 135/x = y cards --(1)
now with 4$ increase she can buy y-12 cards
or say
135/x+4= y-12-(2)
solve 1 & 2
we ger
12x^2+48x-540=0
or say
x=-9, +5
x cannot be -ve
so initial price 5$ , new price ; 5+4 = 9 $
IMO D
so with 135$ , Molly could buy ; 135/x = y cards --(1)
now with 4$ increase she can buy y-12 cards
or say
135/x+4= y-12-(2)
solve 1 & 2
we ger
12x^2+48x-540=0
or say
x=-9, +5
x cannot be -ve
so initial price 5$ , new price ; 5+4 = 9 $
IMO D
kiran120680
