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19 Mar 2019, 07:06
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
55%
(hard)
Question Stats:
69% (02:28) correct
31%
(02:57)
wrong
based on 270
sessions
History
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The difference between a two-digit number and the number obtained by revers-ing its digits is 5 times the sum of the digits of either number. What is the sum of the two digit number and its reverse?
(A) 44
(B) 55
(C) 77
(D) 99
(E) 110
(A) 44
(B) 55
(C) 77
(D) 99
(E) 110
19 Mar 2019, 08:18
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Noshad
Let, Number = ab = 10a+b
Number after reversing digits = ba = 10b+a
(10a+b)-(10b+a) = 5*(a+b)
i.e. 9a - 9b = 5a + 5b
i.e. 9(a-b) = 5(a+b)
which is possible only when a+b = 9 and a-b = 5
i.e. a = 7 and b = 2
Requires sum = 72+27 = 99
Answer: Option D
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