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Bunuel
At an elementary school, the students in third grade, fourth grade, and fifth grade run an average of 12, 15, and 10 minutes per day, respectively. There are twice as many third graders as fourth graders, and twice as many fourth graders as fifth graders. What is the average number of minutes run per day by these students?

A. 12
B. 37/3
C. 88/7
D. 13
E. 14

Let the number of 3rd Graders be A
Let the number of 4th Graders be B
Let the number of 5th Graders be C

According to the question,
\(A=2B\)
\(B=2C\)

If we assume C to be 1, then
\(B=2\)
\(A=4\)

Taking the average
\({12(4) + 15(2) + 10(1)}\) / \({1+2+4}\)

=\(\frac{88}{7}\)
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