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Updated on: 22 Jul 2019, 06:11
Originally posted by Bunuel on 03 Apr 2019, 23:10.
Last edited by Sajjad1994 on 22 Jul 2019, 06:11, edited 1 time in total.
Last edited by Sajjad1994 on 22 Jul 2019, 06:11, edited 1 time in total.
Added Source.
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
35%
(medium)
Question Stats:
74% (02:18) correct
26%
(02:11)
wrong
based on 111
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In the figure, ABCD is a rectangle inscribed in the circle shown. What is the length of the arc DC ?
A. \(\frac{\pi}{4}\)
B. \(\frac{2\pi}{3}\)
C. \(\frac{\pi}{2}\)
D. \(\frac{3\pi}{3}\)
E. \(\frac{4\pi}{3}\)
Source: Nova GMAT
Difficulty Level: 600
Difficulty Level: 600
Attachment:
#GREpracticequestion In the figure, ABCD.jpg [ 26.99 KiB | Viewed 5737 times ]
Archit3110
04 Apr 2019, 02:47
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radius = 2
and we get equilaterlal ∆
60* each
60/360 * 2*pi * 3 = 2pi/3
IMO B
and we get equilaterlal ∆
60* each
60/360 * 2*pi * 3 = 2pi/3
IMO B
Bunuel
rbonito
Joined: 03 Oct 2018
Last visit: 06 Apr 2020
Posts: 4
Given Kudos: 6
Location: United States (NY)
Schools: CBS '22 (A)
GPA: 3.33
10 May 2019, 10:57
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Why isn't the answer E?
L = 2*Pi*R*C/360 (C is the central angle)
R = 2 and we know it's an Equilateral triangle with angles of 60 each, thus would be 2*60.
= 2*Pi*2*120/360
=4Pi/3
Really struggling with this so would really appreciate any insight. Thanks!
L = 2*Pi*R*C/360 (C is the central angle)
R = 2 and we know it's an Equilateral triangle with angles of 60 each, thus would be 2*60.
= 2*Pi*2*120/360
=4Pi/3
Really struggling with this so would really appreciate any insight. Thanks!
