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kiran120680
The product of two positive integers is 96. The sum of the two number is 22. Which of the following could be the difference of the two integers?


A. 2
B. 5
C. 6
D. 8
E. 10

We can create the equations in which x = one number and y = the other number:

xy = 96

and

x + y = 22

x = 22 - y

Substituting, we have:

(22 - y)y = 96

22y - y^2 = 96

y^2 - 22y + 96 = 0

(y - 16)(y - 6) = 0

So y = 16 or 6

When y = 16, x = 6, or when y = 6, x = 16.

So the difference could be 10.

Alternate Solution:

Letting x and y denote the numbers, we are given that x + y = 22 and xy = 96. Let’s find (x + y)^2:

(x + y)^2 = 484

x^2 + 2xy + y^2 = 484

Let’s subtract 4xy = 384 from each side of this equation:

x^2 + 2xy + y^2 - 4xy = 484 - 384

x^2 - 2xy + y^2 = 100

(x - y)^2 = 100

x - y = 10 or x - y = -10

Answer: E
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Products of 96
(1*96,2*48,3*32,4*24,6*16)
Only adding 6 and 16 gives 22.
Therefore the difference is 10

Posted from my mobile device
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i solved it on the basis of logic
Stmt 1 - xy = 96 --Which means either x or y is even
Stmt 2 - x + y = 22 ---Since sum is even therefore both x and y even.

Now unit digit of 96 is 6. Therefore look for number that satisfy these conditions. You will arrive at 16,6 in a jiffy
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