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08 May 2019, 02:24
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D
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Difficulty:
5%
(low)
Question Stats:
81% (00:52) correct
19%
(01:14)
wrong
based on 117
sessions
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If a sequence of 8 consecutive even integers with increasing values has 36 as its eighth term, then the least number in the sequence is
A. 50
B. 48
C. 24
D. 22
E. 20
A. 50
B. 48
C. 24
D. 22
E. 20
08 May 2019, 19:42
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Bunuel
The sequence of 8 consecutive even integers with increasing values are in A.P. with common difference 2.
least number in the sequence would be the 1st number.
1st number=36-7*2=22
Ans. (D)
21 Jun 2019, 08:32
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As the sequence has even integers, the common difference is 2.
As it is given the 8th term is 36.
we have to add 7times 2 to get to the 8th term.
going by the choices, answer choice D fits in i.e. by adding 14 (7 times 2) to the 22 we get the 8th term as 36.
Hence, D
As it is given the 8th term is 36.
we have to add 7times 2 to get to the 8th term.
going by the choices, answer choice D fits in i.e. by adding 14 (7 times 2) to the 22 we get the 8th term as 36.
Hence, D
