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Bunuel
Which of the following lines are perpendicular to the line y=x in the xy-plane?

I. x + y = 0
II. x + y = 1
III. x - y = 2

A. I only
B. II only
C. III only
D. I and II only
E. I, II and III
For two st. lines in the form y=mx +c
If mi*m2= -1 Then perpendicular
m1=m2 then parallel.

given line m=1

Let's find m for
Line I (-1) Perpendicular
Line II (-1) Perpendicular
Line III (1) Parallel

Answer I+II
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ScottTargetTestPrep Even x - y = 2 has a negative slope right? Please correct the way I'm solving this:

- y = -x + 2 = slope of -1
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Bunuel
Which of the following lines are perpendicular to the line y=x in the xy-plane?

I. x + y = 0
II. x + y = 1
III. x - y = 2

A. I only
B. II only
C. III only
D. I and II only
E. I, II and III

Solution:

x - y = 2 has a slope of 1, so it is not true that this line has a negative slope. Notice that the slope is the coefficient of the x-term only when the line is in the so-called “slope-intercept” form, which is y = mx + b. Your equation of -y = -x + 2 is not in the slope-intercept form because the coefficient of the y-term is -1 instead of 1. If you multiply each side of -y = -x + 2 by -1 to obtain y = x - 2, then the line is expressed in the slope-intercept form and the coefficient of the x-term (which is 1) is the (positive) slope of the line.
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