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25 May 2019, 19:41
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
70% (03:06) correct
30%
(03:00)
wrong
based on 228
sessions
History
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A, B and C complete a particular work in 80 days when A and C worked on all 80 days, whereas B worked on every alternate day. A and B can together complete the work in 90 days and A and C in 120 days. In how many days would C alone take to complete the work?
A. 90
B. 150
C. 160
D. 180
E. 360
A. 90
B. 150
C. 160
D. 180
E. 360
firas92
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25 May 2019, 20:18
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(A+B)*90 = 1
(A+C)*120 = 1
80 days of A's input plus 80 days of C's input plus 40 days of B's input completes the full work
80A + 80C + 40B = 1
(A+B/2+C)*80 = 1
Solving the above equations,
C = 1/180 and so C will complete the job alone in 180 days
Answer is (D)
Hit Kudos if this helped!
Posted from my mobile device
(A+C)*120 = 1
80 days of A's input plus 80 days of C's input plus 40 days of B's input completes the full work
80A + 80C + 40B = 1
(A+B/2+C)*80 = 1
Solving the above equations,
C = 1/180 and so C will complete the job alone in 180 days
Answer is (D)
Hit Kudos if this helped!
Posted from my mobile device
26 May 2019, 05:53
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A+B/2+C=1/80
2A+B+2C=1/40.....(1)
A+B=1/90.......(2)
A+C=1/120......(3)
Add (2) and (3)
2A+B+C=7/360......(4)
Subtract (4) from (1)
C= 2/360=1/180
2A+B+2C=1/40.....(1)
A+B=1/90.......(2)
A+C=1/120......(3)
Add (2) and (3)
2A+B+C=7/360......(4)
Subtract (4) from (1)
C= 2/360=1/180
Shashank123abc
