A container consists of x liters of milk. The milk in the container is

Question

A container consists of x liters of milk. The milk in the container is adulterated by adding water equal to 50 percent of the milk in the container. If a person takes out 6 liters of the milk solution from the container, how many liters of water does he take out?

A. 1
B. 2
C. 3
D. 4
E. 5

A. 1
B. 2
C. 3
D. 4
E. 5

Chethan92 · Answer

Imagine the container contains 10 liters of milk.
It is then adulterated by adding 50% of milk's volume of water. i.e, 5 liters of water.
Ratio of Milk : Water = 2:1
In 6 liter of the mixture, the ratio will be 4:2

2 liter of water is taken out.

B is the answer.

Kritisood · Answer

x+0.5x=6
x=6/1.5
0.5x = 0.5*6/15= 2

Babineaux · Answer

The container contains x liters of milk.

Water equals to 50% of the milk was added, thus water quantity =  \frac{x}{2} .

Thus the milk to water ratio = x :  \frac{x}{2}  = 2 : 1;

6 liters of milk was drawn,

Thus within that 6 liters mixture, composition was 4 liters milk and 2 liters water.

Hence, 2 liters of water was drawn.

IMO ans is B.

Vep22 · Answer

This problem can be easily solved using percentages
 
Suppose initially the container had 10L. After Adulteration the container will have 5L(Water) + 5L (Milk)= 10L

Step o1: Someone takes 6Litres so that means 60Percent is removed from the container. Since the water was 5L, so after removing water left = 5-60%of5 ---------->> 5-3 == 2Litres removed

ScottTargetTestPrep · Answer

Solution:
 
In the new solution, where the amount of water equals 50% of the amount of milk in the container, it means that the ratio of water to milk is 1 to 2; therefore, when 6 liters of the milk solution are removed from the container, 2 liters will be water, and the other 4 liters will be milk.

Answer: B

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A container consists of x liters of milk. The milk in the container is

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A container consists of x liters of milk. The milk in the container is

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