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A container consists of x liters of milk. The milk in the container is

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Moderator - Masters Forum
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New post 21 Jun 2019, 09:51
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A container consists of x liters of milk. The milk in the container is adulterated by adding water equal to 50 percent of the milk in the container. If a person takes out 6 liters of the milk solution from the container, how many liters of water does he take out?


A. 1
B. 2
C. 3
D. 4
E. 5
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Re: A container consists of x liters of milk. The milk in the container is  [#permalink]

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New post 21 Jun 2019, 10:28
1
Imagine the container contains 10 liters of milk.
It is then adulterated by adding 50% of milk's volume of water. i.e, 5 liters of water.
Ratio of Milk : Water = 2:1
In 6 liter of the mixture, the ratio will be 4:2

2 liter of water is taken out.

B is the answer.
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Re: A container consists of x liters of milk. The milk in the container is  [#permalink]

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New post 03 Jul 2020, 08:10
x+0.5x=6
x=6/1.5
0.5x = 0.5*6/15= 2
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A container consists of x liters of milk. The milk in the container is  [#permalink]

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New post 03 Jul 2020, 08:42
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The container contains x liters of milk.

Water equals to 50% of the milk was added, thus water quantity = \(\frac{x}{2}\).

Thus the milk to water ratio = x : \(\frac{x}{2}\) = 2 : 1;

6 liters of milk was drawn,

Thus within that 6 liters mixture, composition was 4 liters milk and 2 liters water.

Hence, 2 liters of water was drawn.

IMO ans is B.
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A container consists of x liters of milk. The milk in the container is   [#permalink] 03 Jul 2020, 08:42

A container consists of x liters of milk. The milk in the container is

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