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Bunuel
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let ponies be p
horses are then p+3
total= 2p+3

5/6*1/2*p= some type of ponies that is an integer
5/12*p is an integer hence p is divisible by 12

The minimum value of P can be 12

total= 2*12+3= 27

Answer C
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Bunuel
A ranch has horses and ponies. Five-sixths of the ponies have horseshoes. Half of the ponies with horseshoes are Icelandic. If there are three more horses than ponies, what is the minimum number of horses and ponies on the ranch?

A. 12
B. 15
C. 27
D. 48
E. 54

Minimum number of ponies =12
Minimum number of horses=12+3=15
Minimum number of horses and ponies = 12+15=27

IMO C

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I understand the solutions posted, but doesn't the pair of 9 horses and 6 ponies satisfy the min? There are 3 more horses than ponnies, and you can have 5 ponies with horseshoes (5/6*6) while half of them (6/2=3) would be Icelandic. What am I missing here?
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Let number of ponies be x.


Number of horse shoe ponies = 5x/6


Half of horseshoe are icelandic

5x/12

Now number of ponies has to be an integer so lowest multiple of 6 and 12 = 12.

Then number of horses will be 15.

Total minimum number

12+15 = 27.

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Bunuel
A ranch has horses and ponies. Five-sixths of the ponies have horseshoes. Half of the ponies with horseshoes are Icelandic. If there are three more horses than ponies, what is the minimum number of horses and ponies on the ranch?

A. 12
B. 15
C. 27
D. 48
E. 54

We can let the number of ponies = p

Thus, 5p/6 = horseshoes

1/2 * 5p/6 = 5p/12 = Icelandic

Thus, the minimum number of ponies is 12, and since there are 3 more horses than ponies, the minimum number of horses is 15. Thus, the minimum total is 27.

Answer: C
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