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Bunuel
In triangle ABC, AB=AC and the measure of angle A is twice the measure of angle B. Find the number of degrees in the measures of the exterior angle at C.

(A) 145 degrees
(B) 135 degrees
(C) 125 degrees
(D) 95 degrees
(E) 45 degrees

Since AB = AC, triangle ABC is an isosceles triangle with base angles at B and C and vertex angle at A. Since the base angles of an isosceles triangle are equal in measure, we can let angle B = angle C = x, and thus angle A = 2x. Since the three angles of a triangle sum to 180, we can create the equation:

x + x + 2x = 180

4x = 180

x = 45

Thus, angle C = 45 and the exterior angle at C is 180 - 45 = 135.

Answer: B
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Since AB =AC, it's an Isosceles triangle.

let's take the angle as B

So, 2B+B+B = 180
4B = 180
B = 45

Therefore External angle of C = 180 - 45 = 135

Answer B
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IMO B

Exterior angle = Sum of opposite two interior angles.

Given AB = AC, therefore triangle ABC would wither be an Isosceles or an Equilateral Triangle.

Also < A = 2 * <B, which implies ABC is an Isosceles triangle (Since in Equilateral triangle all the interior angles are equal)

We can also deduce that <B = <C ( since in Isosceles triangle, interior angles of equal sides are equal)

Therefore <A + <B + <C = 180 >>> 2<B + <B + <B = 180 >>> <B = 45

therefore Exterior angle of C = <B + <A
= <B + 2 <B
= 3 (45)
= 135 degrees
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