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We need to find A positive integer with exactly two different divisors greater than 1 must be

Since the number has only two factors greater than 1 so the two numbers should be multiple of each other and the smaller number should not have any factor apart from 1 and the number itself

=> Number should be a square of a Prime number

Ex: \(2^2\) = 4 has only three factors 1, 2, and 4
\(3^2\) = 9 has only three factors 1, 3, and 9

So, Answer will be D
Hope it helps!

Watch the following video to learn the Basics of Prime Numbers

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I have a doubt with this question. So I understand that if we take 4 that is s^2 then we have 2 divisors excluding 1. But what if we take 15 as a number this also has 2 divisors excluding 1 . Why cant we take this number ? Can anyone explain please
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I have a doubt with this question. So I understand that if we take 4 that is s^2 then we have 2 divisors excluding 1. But what if we take 15 as a number this also has 2 divisors excluding 1 . Why cant we take this number ? Can anyone explain please
­
15 has three: 3, 5, and 15 itself.
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