In a right isosceles triangle, the lengths of the two nonhypotenuse si

Question

In a right isosceles triangle, the lengths of the two nonhypotenuse sides are designated a. What is the area of the triangle in terms of a?

A. 1/3*a^2

B.  \frac{\sqrt{2}}{3}*a^2

C. 1/2*a^2

D.  \frac{\sqrt{3}}{2}*a^2

E.  \sqrt{2}a^2

navaneethmmb · Answer

Let ABC be an Isosceles Right triangle with Angle(B) =90 deg
Then by the given data AB = BC = non-hypotenuse sides = 'a' and AC= Hypotenuse

Area of a right triangle = 1/2*base*height

Here the base = height = 'a'
Therefore, Area = (1/2)*a*a = (1/2)a^2

Ans: C

fauji · Answer

Given is Base(a) and Height(a) of a right angled isosceles triangle.

Area = \frac{1}{2}*base*height => \frac{1}{2}* a * a

IMO Answer is Option C!

Abhishek009 · Answer

Hypotenuse of a right isosceles triangle is > The non hypotenuse sides

Now, We have altitude = base of the Triangle = a

So, Area of the triangle is  \frac{1}{2}*a^2 , Answer must be (C)

EgmatQuantExpert · Answer

Solution  
   Given:    
 • In a right isosceles triangle, the lengths of the two non-hypotenuse sides are designated a

To find:    
 • The area of the triangle

Approach and Working Out:    
 • Area of triangle =  \frac{1}{2}  * base * height =  \frac{1}{2}  * a * a =  \frac{a^2}{2}

Hence, the correct answer is Option C.

Answer: C

Kinshook · Answer

Area of the triangle = 1/2 * a * a * sin 90 = 1/2 a^2

IMO C

ScottTargetTestPrep · Answer

Since the area of a right triangle is half the product of its legs and the two legs of the right triangle here are equal to a, then the area is 1/2 * a^2.

Answer: C

In a right isosceles triangle, the lengths of the two nonhypotenuse si

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In a right isosceles triangle, the lengths of the two nonhypotenuse si

Prep Toolkit

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