Last visit was: 25 Apr 2026, 09:49 It is currently 25 Apr 2026, 09:49
Home
Messages
Tests
Schools
Events
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Go to My Error Log Learn more
Close
Request Expert Reply
Confirm Cancel
Back to Forum
Create Topic
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 25 Apr 2026
Posts: 109,827
Own Kudos:
811,227
 [1]
Given Kudos: 105,878
Products:
GMAT Club Tests Forum Quiz
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 109,827
Kudos: 811,227
 [1]
Mike, Scott, Jim, Kate, and Pete each have a different number of assig 10 Dec 2019, 01:43
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
00:00
Start Timer
Pause Timer
Resume Timer
Show Answer
Hide
Show
History
E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

25% (medium)

Question Stats:

76% (01:59) correct 24% (02:13) wrong based on 177 sessions

History

Date
Time
Result
Not Attempted Yet
Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

I. Mike
II. Jim
III. Pete

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


Are You Up For the Challenge: 700 Level Questions
ShowHide Answer
Official Answer
E
User avatar
chetan2u
User avatar
GMAT Expert
Joined: 02 Aug 2009
Last visit: 25 Apr 2026
Posts: 11,229
Own Kudos:
45,018
 [1]
Given Kudos: 335
Status:Math and DI Expert
Location: India
Concentration: Human Resources, General Management
GMAT Focus 1: 735 Q90 V89 DI81
Products:
My Reviews
Expert
Expert reply
GMAT Focus 1: 735 Q90 V89 DI81
Posts: 11,229
Kudos: 45,018
 [1]
Mike, Scott, Jim, Kate, and Pete each have a different number of assig 10 Dec 2019, 02:00
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

I. Mike
II. Jim
III. Pete

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


Are You Up For the Challenge: 700 Level Questions
Show more

Let us work on the inequalities
P<K, K>M, M>J, J>S...
So K>M>J>S
Now P can be anywhere after K as we are looking for COULD

I. M
K>P>M>J>S
II J
K>M>J>S>P
III. P
K>M>P>J>S

All three possible...E
User avatar
exc4libur
User avatar
Joined: 24 Nov 2016
Last visit: 22 Mar 2022
Posts: 1,680
Own Kudos:
1,469
Given Kudos: 607
Location: United States
Posts: 1,680
Kudos: 1,469
Mike, Scott, Jim, Kate, and Pete each have a different number of assig 11 Dec 2019, 07:55
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

I. Mike
II. Jim
III. Pete

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
Show more

p<k, k>m, m>j, j>s, k>m>j>s, k>p
k>[p]>m>j>s: median = m
k>m>[p]>j>s: median = p
k>m>j>[p]>s: median = j

Ans (E)
User avatar
ScottTargetTestPrep
User avatar
Target Test Prep Representative
Joined: 14 Oct 2015
Last visit: 25 Apr 2026
Posts: 22,286
Own Kudos:
26,536
 [1]
Given Kudos: 302
Status:Founder & CEO
Affiliations: Target Test Prep
Location: United States (CA)
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 22,286
Kudos: 26,536
 [1]
Mike, Scott, Jim, Kate, and Pete each have a different number of assig 12 Dec 2019, 19:51
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
Bunuel
Mike, Scott, Jim, Kate, and Pete each have a different number of assignments this month. Pete has fewer assignments than Kate, Kate has more assignments than Mike, Mike has more assignments than Jim, and Jim has more assignments than Scott. Which of the following could be the person who has the median number of assignments this month for the five people listed?

I. Mike
II. Jim
III. Pete

A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III


Are You Up For the Challenge: 700 Level Questions
Show more

We have:

K > P

K > M

M > J

J > S

Using the inequalities above, we can determine the number of assignments (except for Pete) is ordered as:

K > M > J > S

If P > M, then the median is M.

If M > P > J, then the median is P.

If J > P, then the median is J.

Thus, we see that the person with the median number of assignments could be Mike, Pete or Jim.

Answer: E
avatar
ayushg323
avatar
Joined: 29 Jan 2018
Last visit: 03 Nov 2022
Posts: 2
Own Kudos:
5
Given Kudos: 12
Location: India
WE:Social Work (Consulting)
Posts: 2
Kudos: 5
Mike, Scott, Jim, Kate, and Pete each have a different number of assig 16 Dec 2019, 03:11
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Assuming Mike = M, Jim = J, Kate = K, and Pete = P

Given, K>P; K>M; M>J; J>S

From the above, we can say K>P and K>M>J>S

Listing the possibilities now (in increasing order) to calculate the median:

K-M-J-S-P (Median is J)
K-P-M-J-S (Median is M)
K-M-P-J-S (Median is P)

Hence, we have all three possibilities i.e. J,M and P

Answer is E
User avatar
bumpbot
User avatar
Non-Human User
Joined: 09 Sep 2013
Last visit: 04 Jan 2021
Posts: 38,986
Own Kudos:
1,117
Posts: 38,986
Kudos: 1,117
Mike, Scott, Jim, Kate, and Pete each have a different number of assig 19 Sep 2024, 13:34
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Automated notice from GMAT Club BumpBot:

A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.

This post was generated automatically.
Moderators:
Bunuel
Math Expert
109827 posts
Krunaal
Tuck School Moderator
852 posts