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https://www.youtube.com/watch?reload=9&v=DtRN-bFQPIA

OA/OC=OB/OD
2/2=1=3/(5-x) -->x=2

FINAL ANSWER IS (C)
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Triangle BOA & DOC are similar
--> \(\frac{DO}{BO} = \frac{OC}{OA}\)
-->\(\frac{5 - x}{3} = \frac{2}{2} = 1\)
--> \(5 - x = 3\)
--> \(x = 2\)

Option C
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Solution



Given
    • ABCD is a trapezium.

To find
    • The value of x

Approach and Working out

    • △AOB and △COD are similar triangles.
      o So, AO/CO=BO/DO
      o 2/2= 3/5-x
      o 3/5-x=1
      o 5-x=3
      o x=2

Hence, option C is the correct answer.

Correct Answer: Option C
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digonal ratio has to be same as angles of ∆ are same
so
OA/OC = OB/OD
2/2 = 3/5-x
x= 2
IMO C
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From the properties of a trapezium and the figure above,
AB/DC = OB/DO = AO/OC
But AO=2, OC=2, OB=3, and DO=5-x
Hence 2/2 = 3/(5-x)
so 10-2x=6
Hence x=2

The answer is C.
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is the answer C, since one side is 2 and other side is 5. so by symmetry that side should be 3?
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Triangle BOA and DOC are similar triangles

\(\frac{DO}{BO} =\frac{ OC}{OA}\)
\(\frac{(5 - x)}{3} = 1\)
\(5 - x = 3\)
\(x = 2\)


Option C
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A0/0C = BO/OD

2/2=3/5-X


X = 2
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Triangle AOB and triangle DOC — similar triangles
Features of them:
—>\(\frac{AO}{OC}=\frac{ BO}{OD}\)

\(\frac{2}{2}= \frac{3}{(5–x) }\)
5–x = 3
—> x= 2

The answer is C

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