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Solution



To find
We need to determine
    • The remainder when \(7^{52}\) is divided by 2402

Approach and Working out
Rem[\(7^{52}/2402\)] = Rem[\((7^4)^{13}/2402\)] = Rem[\((2402 – 1)^{13}/2402\)] = Rem[\((-1)^{13}/2402\)] = Rem[-1/2402] = 2401

Thus, option A is the correct answer.

Correct Answer: Option A
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We need to find the the remainder when \(7^{52}\) is divided by 2402 ?

We will be solving the problem using Binomial Theorem

We need to break the number into two numbers such that one number is a big number and closer to 2402 and other number is a smaller number

Now, \(7^4\) = 2401 = 2402 - 1

=> \(7^{52}\) = \(7^{4*13}\) = \(7^{4^{13}}\) = \(2401^{13}\) = \((2402-1)^{13}\)

Now, if we use Binomial Theorem to expand this then all the terms except the last term will be a multiple of 2402
=> All terms except the last term will give remainder of 0 when divided by 2402

=> Problem is reduced to what is the remainder when the last term (i.e. 13C13 * 2402^0 * (-1)^13) is divided by 2402
=> Remainder of 1 * 1 * -1 is divided by 2402
=> Remainder of -1 divided by 2402 = -1 + 2402 = 2401

So, Answer will be A
Hope it Helps!

Watch following video to MASTER Remainders by 2, 3, 5, 9, 10 and Binomial Theorem

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To add to the previously posted approaches:

You can calculate \(49^2\) easily by expanding with the binomial theorem: \(49^2=(50-1)^2=50^2-2*50+1^2=2500-100+1=2401\)
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