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10 Mar 2020, 04:20
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
5%
(low)
Question Stats:
91% (01:31) correct
9%
(01:36)
wrong
based on 113
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Seamus has 3 times as many marbles as Ronit, and Taj has 7 times as many marbles as Ronit. If Seamus has s marbles, then, in terms of s, how many marbles do Seamus, Ronit, and Taj have together?
(A) 3s/7
(B) 7s/3
(C) 11s/3
(D) 7s
(E) 11s
(A) 3s/7
(B) 7s/3
(C) 11s/3
(D) 7s
(E) 11s
10 Mar 2020, 04:49
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Bunuel
S = 3R
T = 7R
S+R+T = 3R+R+7R = 11R = 11(S/3) = 11s/3
Answer: Option C
11 Mar 2020, 00:48
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Bunuel
Solution
- • Let us assume that Ronit has r marbles.
- o The number of marbles Seamus has \(= s = 3r ⟹r = \frac{s}{3}………...Eq.(i)\)
o The number of marbles Taj has = 7r
- o Substituting the value of r from Eq(i) into the above equation, we get,
- Thus, the required number of marbles \(= 11r = 11*\frac{s}{3}\)
