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It's given that Amal runs a 30-mile course at a constant rate of 6 miles per hour.
Using D=RT, or T=D/R Time taken by Amal is= 30/6=5 hours.

Also given that Cahaya runs the same course at a constant rate and completes the course in 60 fewer minutes,
then time taken by Cahaya is 4 hours.
Hence using R=D/T, Speed of Cahaya= 30/4 = 7.5 miles per hour

Answer Is Option E.
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Understanding the question

Quote:
Amal runs a 30-mile course at a constant rate of 6 miles per hour.

Distance covered by Amal = 30 mile
Speed of Amal = 6 m/h
Applying the formula ST=D to find Amal's time
6*T = 30
T = 30/6 = 5 hour

Quote:
If Cahaya runs the same course at a constant rate and completes the course in 60 fewer minutes,

Amal's speed is in hour and Cahaya speed is in minutes. There are 60 minutes in 1 hour.
Distance covered by C is 30 miles
Time taken by C = 5-1 = 4 hour
Speed of C = D/T = 30/4 = 7.5 m/h

E is correct
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Amal ran (30/6=) 5 hours.
Cahaya ran = 5-1 = 4 hours.
Question: What is the Rate?

Formula: Distance/R = Time

C = 30/R = 4

R= 7.5 hours.
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