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GMATBusters
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0.2% of (3/4)^2 14 Mar 2020, 19:11
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

Difficulty:

35% (medium)

Question Stats:

61% (01:29) correct 39% (01:50) wrong based on 110 sessions

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GMATBusters’ Quant Quiz Question -3



0.2% of (3/4)^2 *(160/〖10〗^(-2) )=
A) 1.8* 10^-3
B) 1.8* 10^-2
C) 1.8
D) 1.8* 10
E) 1.8* 10^2
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D
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0.2% of (3/4)^2 14 Mar 2020, 19:16
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(0.2/100) * (3/4)*(3/4) * (160/1/100)
(2/1000)* (3/4)*(3/4) * 16000
18
1.8 * 10

Answer = D

(PS: Do not perform the actual multiplication without cancelling out the common terms to reduce the fractions in proper fraction)
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0.2% of (3/4)^2 14 Mar 2020, 19:34
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0.2% of (3/4)^2 *(160/〖10〗^(-2) )=
A) 1.8* 10^-3
B) 1.8* 10^-2
C) 1.8
D) 1.8* 10
E) 1.8* 10^2

0.2/100 * 3/4*3/4 * (160/1/100) 16000
2/1000* 3/4*3/4 * 16000
18
1.8 * 10

Imo. D
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0.2% of (3/4)^2 14 Mar 2020, 20:13
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0.2% of (3/4)^2 *(160/〖10〗^(-2) )=

Lets divide and calculate

(3/4)^2
3/4 = 0.75
0.75^2 = 0.5625

0.2% of 0.5625 = 0.001125

Now (160/〖10〗^(-2) )

10^-2 = -100
160/-100 = -1.60

Now final calculation = 0.001125* - 1.60 = 0.0018

Here we need to look for answer choices that can offer decimal values. So we can safely ignore option C,D and E.

Option B: 1.8*10^-2 = 1.8*1/100 = 0.018
Option A: 1.8*10^-3 = 1.8*1/1000 = 0.0018

Ans: A
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0.2% of (3/4)^2 14 Mar 2020, 21:12
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Quote:

0.2% of (3/4)^2 *(160/〖10〗^(-2) )=
A) 1.8* 10^-3
B) 1.8* 10^-2
C) 1.8
D) 1.8* 10
E) 1.8* 10^2
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0.2% of (3/4)^2 *(160/〖10〗^(-2) )

Lets simplify what we can and not solve
\((2/1000) * (9/16) * (160/(1/100))\)
\((2/1000) * (9/16) * (160*100)\)
\(18\)

We don't have option as 18 so we will have to look deeper.

A) 1.8* 10^-3 - Nope
B) 1.8* 10^-2 - Nope
C) 1.8 - Nope
D) 1.8* 10 = (18/10)*10 = 18 - Works
E) 1.8* 10^2 - Nope

Answer D
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0.2% of (3/4)^2 14 Mar 2020, 21:45
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OA is D
As asked in question 0.2% of (3/4)^2 *(160/ (10) ^(-2) ) is equal to what.
Squaring 3/4 We get 9/16 x 160/10^(-2)
When we have power in negative it automatically become positive in denominator.
So equation will become.
9/16*160*10^2
9*1000
9000
And 0.2% of 9000 is equal to 18
And D option is also giving 18 as answer = 1.8*10=18
So OA is D

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0.2% of (3/4)^2 15 Mar 2020, 01:01
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\(\frac{0.2}{100}\)\((\frac{3}{4})^2\)\((\frac{160}{10^-2})\)
= \(\frac{0.2}{100}\)*\(\frac{9}{16}\)*160*10^2
=0.2*9*10
=1.8*10

Option D
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0.2% of (3/4)^2 15 Mar 2020, 02:20
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Asked: 0.2% of (3/4)^2 *(160/〖10〗^(-2) )=

0.2% of (3/4)^2 *(160/〖10〗^(-2) )= .2/100 * (9/16) * (160 * 100) = .2 * 9 * 10 = 1.8 * 10

A) 1.8* 10^-3
B) 1.8* 10^-2
C) 1.8
D) 1.8* 10
E) 1.8* 10^2

IMO D
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0.2% of (3/4)^2 15 Mar 2020, 04:16
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Answer :D

0.2% of (3/4)^2 X(160/[10]^-2)
0.2 % of 9/16X(160x100)
0.2/100X9/16X16000
=18=1.8x10
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0.2% of (3/4)^2 15 Mar 2020, 06:00
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=0.20/100 * 9/16 *(16*10)/10^(-2)

=0.20 * 9 * 10*(-2+2+1)

=0.20 * 9 * 10^(1)

=1.8 * 10

Therefore, according to me the answer should be option D.

It will be great if some expert can verify.
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