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17 Mar 2020, 02:25
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
85%
(hard)
Question Stats:
49% (02:34) correct
51%
(02:02)
wrong
based on 130
sessions
History
Date
Time
Result
Not Attempted Yet
There are 5 line segments of lengths 2, 3, 4, 5 and 6 cm. What is the probability that three randomly chosen line segments cannot form a triangle?
A. 1/5
B. 3/10
C. 2/5
D. 1/2
E. 7/10
Are You Up For the Challenge: 700 Level Questions
A. 1/5
B. 3/10
C. 2/5
D. 1/2
E. 7/10
Are You Up For the Challenge: 700 Level Questions
Updated on: 23 Mar 2020, 05:40
Originally posted by GMATinsight on 17 Mar 2020, 02:50.
Last edited by GMATinsight on 23 Mar 2020, 05:40, edited 1 time in total.
Last edited by GMATinsight on 23 Mar 2020, 05:40, edited 1 time in total.
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Bunuel
Property
For a Triangle to exist Sum of any two sides MUST be greater than Third side
Total ways of choosing any 3 out of 5 lengths = 5C3 = 10 ways
favorable cases which will NOT form Triangle = {2, 3, 5} {2, 3, 6} {2, 4, 6} = 3 cases
Favorable Probability = 3/10
Answer: Option B
17 Mar 2020, 02:57
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GMATinsight
I think you have mistaken the question is about probability of unfavourable cases the answer is 3/10
Posted from my mobile device
