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Bunuel
In how many seconds a train moving at 18 kilometers per hour cross a bridge which is 270 meters long?

A. 70 sec
B. 72 sec
C. 140 sec
D. 144 sec
E. 146 sec

Asked: In how many seconds a train moving at 18 kilometers per hour cross a bridge which is 270 meters long?

18 km/hr = 18*1000/60*60 = 5 m/s
Let seconds required for a train moving at 18 kilometers per hour cross a bridge which is 270 meters long = t seconds
270 m = 5 m/s *t
t = 270 /5 = 54 seconds

Hi Bunuel
I think train length is also required.
None of the answers seem correct with available data.

Yes, of course. Edited. Thank you.
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Bunuel
In how many seconds a 90-meter long train moving at 18 kilometers per hour cross a bridge which is 270 meters long?

A. 70 sec
B. 72 sec
C. 140 sec
D. 144 sec
E. 146 sec

Asked; In how many seconds a 90-meter long train moving at 18 kilometers per hour cross a bridge which is 270 meters long?

18 km/hr = 18*1000/(60*60) = 5 m/s
Let the time required for a 90-meter long train moving at 18 kilometers per hour cross a bridge which is 270 meters long = t secs
270 + 90 = 360 = 5 m/s * t
t = 360 /5 = 72 secs

IMO B
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Bunuel
In how many seconds a 90-meter long train moving at 18 kilometers per hour cross a bridge which is 270 meters long?

A. 70 sec
B. 72 sec
C. 140 sec
D. 144 sec
E. 146 sec

total length = 90+270 ; 360 mtrs
18 kmph = 18*1000/3600 ; 5 m/sec
so net time ; 360/5 ; 72 sec
IMO B
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