Bunuel
If \(pqr = 1\) then \(\frac{1}{1 + p + q^{−1}} + \frac{1}{1 + q + r^{− 1}} + \frac{1}{1 + r + p^{−1}}\) is equivalent to
A. \(p + q + r\)
B. \(\frac{1}{p + q + r}\)
C. \(p^{− 1} + q^{− 1} + r^{− 1}\)
D. 1
E. 2
Are You Up For the Challenge: 700 Level QuestionsHere's the question:
If \(pqr = 1\) then \(\frac{1}{1 + p + q^{−1}} + \frac{1}{1 + q + r^{− 1}} + \frac{1}{1 + r + p^{−1}}\) is equivalent to
Notice that, in a question that works like this one, with the variables defined in one expression and then used in an expression that generates the correct answer, it must the case that
all sets of values that fit the first expression must, when used in the second expression, generate the same result.This principle is super valuable in GMAT quant, and it can be applied to many types of questions. Another example is a question in which the correct answer is based on a triangle with certain parameters.
All triangles with those parameters must generate the same result. So, if the easiest way to solve the question is, for instance, to use a right triangle with those parameters, then you can use a right triangle.
Thus, in this case, all values for for p, q, and r such that \(pqr = 1\) will generate the same result when they are placed in the second expression.
So, one way you could answer this question is to choose any set of values such that \(pqr = 1\).
So, let's see what happens if we make p, q, and r all 1, since 1 x 1 x 1 = 1.
\(\frac{1}{1 + 1 + 1} + \frac{1}{1 + 1 + 1} + \frac{1}{1 + 1 + 1}\) =
\(\frac{1}{3} + \frac{1}{3} + \frac{1}{3}\) = 1
The correct answer is (D).