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Sub 505 (Easy)|   Arithmetic|      
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CAMANISHPARMAR
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A clothing store’s total opening-year sales were $50,000. The total... 01 Apr 2020, 22:23
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C
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!

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5% (low)

Question Stats:

89% (01:38) correct 11% (02:27) wrong based on 120 sessions

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A clothing store’s total opening-year sales were $50,000. The total sales increased by 20% in the second year, increased by 10% in the third year, and decreased by 5% in the fourth year. What was the total amount of the store’s sales (in whole dollars) in year 4?

A) $19,300
B) $62,500
C) $62,700
D) $67,500
E) $69,300
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C
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A clothing store’s total opening-year sales were $50,000. The total... 01 Apr 2020, 22:31
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CAMANISHPARMAR
A clothing store’s total opening-year sales were $50,000. The total sales increased by 20% in the second year, increased by 10% in the third year, and decreased by 5% in the fourth year. What was the total amount of the store’s sales (in whole dollars) in year 4?

A) $19,300
B) $62,500
C) $62,700
D) $67,500
E) $69,300
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Let, Sales in 1st year = 100

Sales in 2nd year = 100+20% of 100 = 120

Sales in 3rd Year = 120 + 10% of 120 = 132

Sales in 04th year = 132-5% of 132 = 132 - 6.6 = 125.4

If 100 = 50000 ( in real)

then, 125.4 = 50,000*125.4/100 = 62700

Answer: Option C
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A clothing store’s total opening-year sales were $50,000. The total... 03 Apr 2020, 07:26
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CAMANISHPARMAR
A clothing store’s total opening-year sales were $50,000. The total sales increased by 20% in the second year, increased by 10% in the third year, and decreased by 5% in the fourth year. What was the total amount of the store’s sales (in whole dollars) in year 4?

A) $19,300
B) $62,500
C) $62,700
D) $67,500
E) $69,300
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Initially I tried going the multiplication route and quickly things spiraled out of control.

Basically this is what I tried: 50,000 * 1.20 *1.10 * 0.95 = x
On calculator this works, but the large numbers quickly spiraled out of control and took a lot of time.

So just by some mental math.

50,000 + 10% + 10% = 60,000
60,000 + 10% = 66,000
66,000 - 5% (10% = 6600, thus 5% equals to 3300) = 66000 - 3300 = $62,700

Thus answer C
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A clothing store’s total opening-year sales were $50,000. The total... 03 Apr 2020, 08:01
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CAMANISHPARMAR
A clothing store’s total opening-year sales were $50,000. The total sales increased by 20% in the second year, increased by 10% in the third year, and decreased by 5% in the fourth year. What was the total amount of the store’s sales (in whole dollars) in year 4?

A) $19,300
B) $62,500
C) $62,700
D) $67,500
E) $69,300
Show more

Increased by 20% -> Multiply by \(\frac{6}{5}\)

Increased by 10% -> Multiply by \(\frac{11}{10}\)

Decreased by 5% -> Multiply by \(\frac{19}{20}\)

Then the final answer would be \(50000 * \frac{6}{5} * \frac{11}{10} * \frac{19}{20} = 50000 * \frac{6*11*19 }{ 5*10*20}\\
=\frac{50000}{1000 }* 6 * 11 * 19 = 50 * 66 * 19 = 3300 * 19\).

We can see the last digits must be 300*9 = 2700 -> 700, and only C ends in 700.

Ans: C
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Solution



Given
In this question, we are given that
    • A clothing store’s total opening-year sales were $50,000.
    • The total sales increased by 20% in the second year, increased by 10% in the third year, and decreased by 5% in the fourth year.

To find
We need to determine
    • The total amount of the store’s sales (in whole dollars) in year 4.

Approach and Working out
    • 20% increase = x (6/5)
    • 10% increase = x (11/10)
    • 5% decrease = x (95/100)
    • Hence, cumulative change = 6/5 * 11/10 * 95/100 = 6*11*19/1000

Therefore, the final value = 50000 * 6*11*19/1000 = 50*6 *11*19 = 62700
Thus, option C is the correct answer.

Correct Answer: Option C
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A clothing store’s total opening-year sales were $50,000. The total... 04 Apr 2020, 06:51
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50000×1.2×1.1×0.95=62700
Option c is the answer

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