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Bunuel
\(\frac{1}{3} +\frac{1}{3}\) equals how many twelfths?


(A) 2
(B) 4
(C) 6
(D) 8
(E) 9

1/3 + 1/3 = 2/3

let 2/3 = a (1/12)

so a = 12*(2/3) = 8

IMO D
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Bunuel
\(\frac{1}{3} +\frac{1}{3}\) equals how many twelfths?


(A) 2
(B) 4
(C) 6
(D) 8
(E) 9
\(\frac{2}{3} = \frac{x}{12}\)

Or, \(x = 8\), Answer must be (D)
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Bunuel
\(\frac{1}{3} +\frac{1}{3}\) equals how many twelfths?


(A) 2
(B) 4
(C) 6
(D) 8
(E) 9

Since 1/3 + 1/3 = 2/3 and , (2/3) / (1/12) = 2/3 x 12 = 8, 1/3 + 1/3 is equal to 8 twelfths.

Answer: D
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